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Learning python SyntaxError: 'return' outside function
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Learning python SyntaxError: 'return' outside function
#1
Here is my code:

import string 
letters_guessed = ['x', 'i', 'k', 'p', 'r', 's', 'z', 'h', 'b'] 
alpha = string.ascii_lowercase
available_letters = alpha
def get_available_letters(letters_guessed):
    '''
    letters_guessed: list (of letters), which letters have been guessed so far
    returns: string (of letters), comprised of letters that represents which letters have not
      yet been guessed.
    '''
for char in (alpha):
    print(char)
    if char in (letters_guessed):
        available_letters = available_letters.replace(char,'')
        print(available_letters)
This code does what it should. It gives a printout of the alphabet minus letters guessed. ANYTIME I try to add a return statement ANYWHERE in this code I get either SyntaxError: 'return' outside function or IndentationError: unexpected indent. I have tried indenting everything in every manner I can manage. Please help.
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#2
Please proper tags when posting code.
I welcome all feedback.
The only dumb question, is one that doesn't get asked.
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my-python
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#3
The lines from for char in (alpha): onwards are not indented into the function get_available_letters
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#4
Also, when debug error - always post the full traceback (in error tags) alongside the actual code that produce it (in python tags).
(Aug-03-2020, 02:49 AM)Grale1953 Wrote: This code does what it should.
This code (as is now) will produce error
If you can't explain it to a six year old, you don't understand it yourself, Albert Einstein
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