Trying to find first 2 letter word in a list of words

[Oldman45]

Hello

I am trying to get this function working but cannot work out what is wrong. Any help will be gratefully received. My input is:

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xs = ["this", "is", "a", "dead", "parrot"]   def find_first_2_letter_word(xs):     for wd in xs:         if len(wd) == 2:             return wd         return " "       print("The first 2 letter word is ", find_first_2_letter_word(xs))

My output is:

Output:
Python 3.8.4 (tags/v3.8.4:dfa645a, Jul 13 2020, 16:46:45) [MSC v.1924 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license()" for more information.
>>> 
================== RESTART: C:\Users\John\Desktop\testing1.py ==================
The first 2 letter word is   
>>> 

As can be seen the program prints the statement but fails to show the first 2 letter word.

Thank you

[ndc85430]

Hint: what happens on the first iteration of the for loop (i.e. when wd is "this")?

[Oldman45]

Hello ndc85430

I am trying to teach myself Python from How to Think Like a Computer Scientist so I must admit to being very much a tyro, please forgive my lack of knowledge. Now answering your hint I think that the first iteration passing over "this" produces a False and so the function should continue on to the second word in the list "is", which is a 2 letter word so the function should return True and stop iterating at that point and move to the print command outputting "The first 2 letter word is is". I still cannot see why the function does not do this.

[Intr0spective]

Hi,

first iteration passing over "this" produces a False and so the function should continue on to the second word in the list "is",

This is not happening, hence the code does not work.

The following loop:

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for wd in xs:         if len(wd) == 2:             return wd         return " "

will not loop through the whole list simply because the code checks:

1	if len(wd) == 2:

- the condition is not met since ,,this,, is 4 characters long.

Therefore the code moves on to:

1	return " "

- this simply exits the for loop returning empty string " " and the code then moves on to:

1	print("The first 2 letter word is ", find_first_2_letter_word(xs))

You do not want to exit the loop after the first iteration :) Delete/comment out the line that makes the loop exit and the code should work.

[perfringo]

Hint in more direct flavour: first word will return either word itself (if length is 2) or empty string. For-loop never reaches the second word. Remedy: move return of empty string out of for-loop.

[Oldman45]

Hello IntrOspective

Very helpful and informative thank you for your time and interest. I have learnt something there. I am using How to Think Like a Computer Scientist to teach myself Python and in that book they stated the function, including the 'return " "'. I find that quite misleading.

Thanks again

[Intr0spective]

No worries,

Since you mentioned that the code comes from the book - i have just had a look at it again - in fact you can get the code working with ,,return " ",, too.

Have a look at the code in your book and see how exactly is ,,return " ", indented..
The way it was indented in your original code it was in fact part of the loop and hence causing trouble.

Therefore, the code in book is not necessarily misleading :)

[Oldman45]

Hello IntrOspective

I have only just seen this - thank you for your continued support.

I have looked in the book and it took me some time to spot it but you are correct, thank you.

I am really struggling to get my head around writing programmes with functions and now have had to seek help on my latest attempt in trying to compute a distance.

Never mind onwards it is.