##### Largest product in a grid (projecteuler problem11)
 Largest product in a grid (projecteuler problem11) tragical Unladen Swallow Posts: 1 Threads: 1 Joined: Sep 2020 Reputation: Sep-11-2020, 04:56 PM Hello everyone, I just started learning the Python language and came across a very interesting Euler project, problem 11, the code I wrote seems to work, but it is very large and difficult to understand, tell me how to do better. please no ridicule, i only study it for a week (https://projecteuler.net/problem=11) ```from array import * tmp1=1 tmp=1 tmp2=1 tmp3=1 suma=1 suma2=1 suma1=1 suma3=1 masiv=[8, 2, 22, 97, 38, 15, 0 , 40, 0, 75, 4, 5, 7, 78, 52, 12, 50, 77, 91, 8, 49, 49, 99, 40, 17, 81, 18, 57, 60, 87, 17, 40, 98, 43, 69, 48, 4, 56, 62,0,81, 49, 31, 73, 55, 79, 14, 29, 93, 71, 40 ,67 ,53, 88, 30 ,3 ,49, 13 ,36, 65,52, 70 ,95, 23, 4 ,60, 11 ,42, 69, 24 ,68, 56, 1 ,32 ,56, 71, 37, 2, 36, 91,22, 31, 16 ,71, 51 ,67, 63, 89, 41, 92 ,36 ,54 ,22 ,40 ,40 ,28, 66, 33, 13, 80,24, 47, 32 ,60 ,99, 3 ,45, 2 ,44 ,75, 33, 53 ,78 ,36 ,84 ,20, 35, 17, 12, 50,32, 98, 81 ,28, 64, 23, 67 ,10, 26, 38, 40, 67, 59, 54, 70, 66 ,18 ,38 ,64, 70,67 ,26 ,20 ,68 ,2 ,62, 12, 20, 95, 63, 94 ,39, 63, 8 ,40 ,91 ,66 ,49, 94, 21,24, 55, 58 ,5 ,66, 73, 99, 26, 97, 17, 78, 78 ,96 ,83, 14 ,88 ,34 ,89 ,63, 72,21, 36 ,23 ,9 ,75 ,0 ,76, 44, 20, 45 ,35, 14, 0 ,61, 33, 97, 34, 31, 33, 95,78, 17, 53, 28 ,22, 75, 31, 67, 15, 94 ,3 ,80, 4, 62, 16, 14, 9 ,53, 56, 92,16 ,39 ,5 ,42, 96 ,35 ,31 ,47 ,55, 58, 88 ,24 ,0 ,17 ,54, 24 ,36, 29, 85, 57,86, 56, 0, 48, 35, 71, 89, 7, 5, 44, 44, 37, 44, 60 ,21, 58 ,51, 54, 17, 58,19, 80, 81, 68, 5 ,94, 47, 69, 28, 73, 92, 13, 86, 52, 17, 77 ,89, 55, 40,4, 52, 8, 83, 97 ,35 ,99, 16, 7, 97 ,57 ,32 ,16, 26, 26, 79, 33 ,27, 98, 66,88, 36, 68, 87, 57, 62 ,20, 72, 3 ,46, 33, 67, 46, 55, 12, 32, 63, 93, 53, 69,4 ,42, 16, 73, 38, 25, 39, 11, 24, 94, 72, 18, 8, 46, 29, 32, 40, 62, 76, 36,20, 69, 36, 41, 72, 30, 23, 88, 34, 62, 99, 69, 82 ,67, 59, 85, 74, 4 ,36, 16,20, 73, 35, 29, 78, 31 ,90 ,1 ,74 ,31, 49, 71, 48, 86 ,81, 16, 23, 57, 5, 54,1 ,70, 54, 71, 83 ,51, 54, 69, 16 ,92 ,33 ,48 ,61 ,43 ,52, 1 ,89 ,19 ,67, 48] for r in range(0,336): j=-21 j=-21+r tmp=1 #print('') for i in range(1,5): j+=21 #print(masiv[j]) tmp*=masiv[j] #print(tmp) if sumasuma1: rez=suma else: rez=suma1 if suma2>suma3: rez1=suma2 else: rez1=suma3 if rez1>rez: print(rez1) else: print(rez)``` Reply Posts: 3,120 Threads: 44 Joined: Jan 2018 Reputation: Sep-14-2020, 01:03 PM Here is a code which I find better. I use a double list of length 20 which items are lists of size 20 (the rows of the table). Then I use a function to generate the 4-uples of indices corresponding to 4 neighbor numbers in all the possible ways. Finally I select the maximum score ```data = """ 08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08 49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00 81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65 52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91 22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80 24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50 32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70 67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21 24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72 21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95 78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92 16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57 86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58 19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40 04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66 88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69 04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36 20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16 20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54 01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48""" def segments(n, m): for i in range(n): for j in range(m): if j+3 < m: yield ((i, j), (i, j+1), (i, j+2), (i, j+3)) if i+3 < n: yield ((i, j), (i+1, j+1), (i+2, j+2), (i+3, j+3)) if i-3 >= 0: yield ((i, j), (i-1, j+1), (i-2, j+2), (i-3, j+3)) if i+3 < n: yield ((i, j), (i+1, j), (i+2, j), (i+3, j)) def score(seg, table): p = 1 for i, j in seg: p *= table[i][j] return p if __name__ == '__main__': table = [[int(x) for x in row.split()] for row in data.strip().split('\n')] n, m = len(table), len(table[0]) print(max(score(seg, table) for seg in segments(n, m)))`````Output:70600674`` Reply

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