list1 position = list 2?

[Nickd12]

lets say I have two lists
list1 = [1, 2, 3, 4, 5]
list2 = [6, 7, 8, 9, 10]

say list 1 position 0 is an input so the number 1
I want to return list 2 with that same position as an output
so I would like to return the 6

basically what would be my return statement for this?

[bowlofred]

Lists are indexed at 0, not at 1, so you'd have to subtract 1 if you want 1 to represent the first element.

If you expected to return the first element of the second list, it would be list2[0]. So replace the 0 with (one less than) the result you had: list1[0].

Putting it together: list2[list1[0] - 1]

>>> list1 = [1, 2, 3, 4, 5]
>>> list2 = [6, 7, 8, 9, 10]
>>> list2[list1[0] - 1]
6

[Nickd12]

the items in the list are words not numbers I just used numbers as an example
here is my code

def cmd(text):
    CMD_INPUTS = ['pause']
    CMD_OUTPUTS = ['input keyevent 85']

    for word in text.split():
        if word.lower() in CMD_INPUTS:
            
            return

there will be more inputs and outputs but I only have one in there for now. What I want to do
is if pause is in the text I want it go check the position of pause in the CMD_INPUTS and return the item that's in that same position but in CMD_OUTPUTS sorry I should've been more clear

---

also note that its not like a one time return the return will always change based on the input

[bowlofred]

list.index() gives you the position within a list.

>>> INPUT=["the", "quick", "brown", "fox", "jumped"]
>>> OUTPUT=["Now", "is", "the", "time", "for"]
>>> word = "fox"
>>> OUTPUT[INPUT.index(word)]
'time'

[Nickd12]

I think I got it idk if its sound though

def test(text):


    list1 = ['1', '2', '3', '4', '5']
    list2 = ['6', '7', '8', '9', '10']
    for word in text.split():


        if word.lower() in list1:
            x = list1.index(text)
            return list2[x]

---

haha didn't see your reply yeah pretty much same thing but yours is a bit more clean so ill go with that but thank you.