Need urgent help

[OneTwo]

Hi,
How to take a word and put the letters into separate indexes of an array instead of putting the letters into 1 index?
Thanks

[Gribouillis]

Here is a way

>>> word = "python"
>>> list(word)
['p', 'y', 't', 'h', 'o', 'n']

[OneTwo]

Yes, but then if I want to read the word into an array, than it reads all the letters into 1 index instead of putting the letters into separate indexes.

[Gribouillis]

I'm using ordinary Python lists, I don't know what you mean by 'array'

>>> word = "python"
>>> L = list(word)
>>> L
['p', 'y', 't', 'h', 'o', 'n']
>>> ''.join(L)
'python'

[OneTwo]

By array I mean normal lists, and Is there a way I can send you a screenshot of what I mean?

[perfringo]

Let's take ambiguity out of the way. Are we talking about arrays or lists?

Other than that:

>>> list_ = list('python')
>>> for item in list_:
...     print(f'Letter {item} is at index {list_.index(item)}')
...
Letter p is at index 0
Letter y is at index 1
Letter t is at index 2
Letter h is at index 3
Letter o is at index 4
Letter n is at index 5

[OneTwo]

I mean lists, this is it:
n=input()
t=[]
t.append(list(n))

and than all the letters of the word go in the first index.

[bowlofred]

Don't append it (which adds the list into a single element), extend it.

word_letters = list("python")

t = []
t.append(word_letters)
print(f"After append, the first element is {t[0]}")

t = []
t.extend(word_letters)
print(f"After extend, the first element is {t[0]}")

Output:
After append, the first element is ['p', 'y', 't', 'h', 'o', 'n']
After extend, the first element is p

[perfringo]

There is method for that. And this ain't append. It's extend:

>>> list_ = list('python')
>>> my_list = []
>>> my_list.extend(list_)
>>> my_list
['p', 'y', 't', 'h', 'o', 'n']

EDIT: ninjad by bowlofred

Alternatively you can do something like this:

>>> answer = 'python'
>>> list_ = [*answer]
>>> list_
['p', 'y', 't', 'h', 'o', 'n']

[OneTwo]

Thank you guys soo much for the help, it worked!!