reverse math in python, who will find the correct answer?

[Kakha]

'''
this formula is calculated from right to left, but only if a = c, for example: 11 * 15, 55 * 59, 97 * 92
who can change the formula so that it counts when a != c for example: 11 * 35, 55 * 19, 97 * 42
(a b c d < 10)
'''
a = 1
b = 2
c = a
d = 9


sum1 = b * d
D1=sum1 % 10
D1_Memo= sum1 // 10

sum2 =(b+d)*a + D1_Memo

D2=sum2 % 10
D2_Memo= sum2 // 10

D3 = a * c + D2_Memo

print(a,b,"*",c,d,"=",D3,D2,D1)

Output:
1 2 * 1 9 = 2 2 8

[buran]

Is there question here? It's completely unclear what your goal is.

[Kakha]

Is there question here?

Yes

[buran]

[Kakha]

the function calculates all multiplications for numbers 0-99 that start with the same digit
you need to get a formula that works for all numbers 0-99 that don't start with the same digit
25 * 99
27 * 58

[buran]

the function calculates all multiplications for numbers 0-99 that start with the same digit
you need to get a formula that works for all numbers 0-99 that don't start with the same digit

there is NO function present in your code.
And we don't need to do anything - it's you [home]work. If you want help, help us to help you, don't make us guess.

[Kakha]

the function calculates all multiplications for numbers 0-99 that start with the same digit
you need to get a formula that works for all numbers 0-99 that don't start with the same digit

there is NO function present in your code.
And we don't need to do anything - it's you [home]work. If you want help, help us to help you, don't make us guess.

this is a question for mathematicians

[Gribouillis]

Replace (b + d)*a by a*d + b*c and it will work.

[Kakha]

Replace (b + d)*a by a*d + b*c and it will work.

'''
thanks Gribouillis it works !!!
'''
a = 1
b = 5
c = 9
d = 4


sum1 = b * d
D1=sum1 % 10
D1_Memo= sum1 // 10

sum2 =a*d + b*c + D1_Memo

D2=sum2 % 10
D2_Memo= sum2 // 10

D3 = a * c + D2_Memo

print(a,b,"*",c,d,"=",D3,D2,D1)

Output:
1 5 * 9 4 = 14 1 0

[Gribouillis]

Note that

D1=sum1 % 10
D1_Memo= sum1 // 10

can be shortened in

D1_Memo, D1 = divmod(sum1, 10)