Top 3 students

[banidjamali]

Hello everyone. Hope you are all having a great time.

Here's a simple question:

There's a dictionary, and I want to extract the top 3 students from it.
I have successfully achieved the goal and the code is pretty much readable (I suppose), but I'm sure there's a more concise way of achieving the same output (using less lines of code).

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scores = {'Josh': 90, 'Adam': 72, 'Amin': 81, 'Narnia': 56, 'Natalie': 65, 'David': 68, 'Karen': 92, 'Elsa': 75}   names = list(scores.keys()) values = list(scores.values()) values.sort()   x = 1 for i in values:     while x < 4:         print(f"Top {x}:", names[-x] ,values[-x])         x += 1

Output:
Top 1: Elsa 92
Top 2: Karen 90
Top 3: David 81

Thank you all in advance.

[buran]

sort scores, you can pass key argument to sort().

I have successfully achieved the goal

also check the output of your code - it's incorrect, because you sort keys and values separately

[Serafim]

Just a comment: You sort the values but the name list is still untouched so the names and values in the result are no longer connected. You get the three highest values but the last three names. The output ought to be:
Top 1: Karen 92
Top 2: Josh 90
Top 3: Amin 81

which can be achieved by sorting the dictionary by value (or by item, which I think is the terminology here, but I'm far from sure). Use sorted and provide a key function (which has to be a lambda function as it will be "in-line"):

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scores = {'Josh': 90, 'Adam': 72, 'Amin': 81, 'Narnia': 56, 'Natalie': 65, 'David': 68, 'Karen': 92, 'Elsa': 75} scores = sorted(scores.items(), key=lambda x: x[1], reverse=True) for i in range(3):     print(f"Top {i+1}: {scores[i][0]} {scores[i][1]}")

[Serafim]

Another comment: The method given in my previous post gives a list of tuples. If you want an ordered dictionary (a contradiction as dictionaries are normally nor ordered) you may turn the list into a dictionary by simply:

1	scores = dict(sorted(scores.items(), key=lambda x: x[1], reverse=True))

also, if you need the original dictionary for other purposes in your program you might give the sorted dictionary another name like "sorted_scores" or something.

[banidjamali]

scores = sorted(scores.items(), key=lambda x: x[1], reverse=True)

Yes, I didn't notice the mistake in my output!
This line really helped.
Thank you all.