Create variable and list dynamically

[quest_]

Hello,

This is a simple function:

number =3
a, b, c = cirq.LineQubit.range(number)

And I want to create these variables (a, b, c) dynalically instead of writing by hand. However I know that, creating variable with this method not so good. So I wanted to ask here. What is the best way for that. Because sometimes I need to create 10 variable sometimes 3 and I do not want to write or do not want to correct each time. After creating these variable I need to save them in a list too

[bowlofred]

Don't create them as separate variables in your namespace. Instead assign the variables to a collection, and pull out the values as needed. cirq.LineQubit.range(number) is already returning a list. Your assignment is just unpacking it into separate variables.


Instead consider:

number = 3
all_qbits = cirq.LineQubit.range(number)
print (all_qbits)

Output:
[cirq.LineQubit(0), cirq.LineQubit(1), cirq.LineQubit(2)]

[quest_]

Don't create them as separate variables in your namespace. Instead assign the variables to a collection, and pull out the values as needed. cirq.LineQubit.range(number) is already returning a list. Your assignment is just unpacking it into separate variables.


Instead consider:

number = 3
all_qbits = cirq.LineQubit.range(number)
print (all_qbits)

Output:
[cirq.LineQubit(0), cirq.LineQubit(1), cirq.LineQubit(2)]

Thanks it is true! But it could be nice to know logic. Because I also do following script dynalmically:
If I have 1 variable, it will be

a =kron(unitary(rz(qbt[0]))) 

If I have 2 vaarible, it will be

a = kron(unitary(rz(qt[0])),unitary(rz(qbt[1]))) 

and if I have 10, it will go...

HOw can I do it automatically?

[bowlofred]

Is that a typo and the second call should be qbt[0] rather than qt[0]? If so, we can probably write a program to index it. If it's not a typo, I don't know how you'd expect anything to understand which sequence it's using.

The problem there isn't the assignment, it's the call. You have two different calls to kron(). I don't know what that function does, so there might be easier ways to do it, but you could construct a list with your arguments, then pass the list into kron(). Something like:

def kron_argument_list(number):
    arg_list = []
    for i in range(number):
        arg_list.append(unitary(rz(qbt[i])))
    return arg_list

a = kron(*kron_argument_list(1))
a = kron(*kron_argument_list(2))

[quest_]

Is that a typo and the second call should be qbt[0] rather than qt[0]? If so, we can probably write a program to index it. If it's not a typo, I don't know how you'd expect anything to understand which sequence it's using.

The problem there isn't the assignment, it's the call. You have two different calls to kron(). I don't know what that function does, so there might be easier ways to do it, but you could construct a list with your arguments, then pass the list into kron(). Something like:

def kron_argument_list(number):
    arg_list = []
    for i in range(number):
        arg_list.append(unitary(rz(qbt[i])))
    return arg_list

a = kron(*kron_argument_list(1))
a = kron(*kron_argument_list(2))

Thanks yes it is a typo! and if I have 1 varibale, then kron argument will include 1 variable with unitary if I have 2 variable then kron argument will include 2 argument with unitaries. I will try your method and If it is not work, I will let you know
Thanks again

Forgat to ask: a = kron(*kron_argument_list(2)) means that a = kron(*kron_argument_list(number))?? or what it means??

When I write a = kron(*kron_argument_list(2)) is this equal to write a = kron(unitary(rz(qt[0])),unitary(rz(qbt[1])))??

[bowlofred]

Yes, it should. I can't actually test it, because I don't have any of your functions or data structures.

You could call the function directly and see the argument list that it generates.

print(kron_argument_list(1))
print(kron_argument_list(2))

[nilamo]

If I have 2 vaarible, it will be

a = kron(unitary(rz(qt[0])),unitary(rz(qbt[1]))) 

and if I have 10, it will go...

HOw can I do it automatically?

The * expands lists for exactly this reason.

>>> def show(a=1, b=2, c=3):
...   print(a, b, c)
...
>>> show('cat')
cat 2 3
>>> items = ['spam', 'foo']
>>> show(*items)
spam foo 3

[quest_]

If I have 2 vaarible, it will be

a = kron(unitary(rz(qt[0])),unitary(rz(qbt[1]))) 

and if I have 10, it will go...

HOw can I do it automatically?

The * expands lists for exactly this reason.

>>> def show(a=1, b=2, c=3):
...   print(a, b, c)
...
>>> show('cat')
cat 2 3
>>> items = ['spam', 'foo']
>>> show(*items)
spam foo 3

Apologize but I did not understand anyhting. Why are we seeing "spam foo 3" instead of "spam foo" when we run "show(*items)"

[quest_]

Yes, it should. I can't actually test it, because I don't have any of your functions or data structures.

You could call the function directly and see the argument list that it generates.

print(kron_argument_list(1))
print(kron_argument_list(2))

I wrote your function and when I called function like that:

a = kron(*kron_argument_list([i for i in range(qbt)]))

I have this error:

TypeError: 'tuple' object cannot be interpreted as an integer

And I have this error: TypeError: 'tuple' object cannot be interpreted as an integer, when I tried the following script

a = kron(*kron_argument_list(qbt))

[nilamo]

The * expands lists for exactly this reason.

>>> def show(a=1, b=2, c=3):
...   print(a, b, c)
...
>>> show('cat')
cat 2 3
>>> items = ['spam', 'foo']
>>> show(*items)
spam foo 3

Apologize but I did not understand anyhting. Why are we seeing "spam foo 3" instead of "spam foo" when we run "show(*items)"

Because show() is always printing a, b, and c. The list that was expanded only had 2 elements, so only a and b had values coming from the list, while c still had it's default value as defined in the argument list: def show(a=1, b=2, c=3):

a = kron(*kron_argument_list([i for i in range(qbt)]))

I have this error:

Error:
TypeError: 'tuple' object cannot be interpreted as an integer

What value does qbt have? I think the error is coming from range(qbt), and that qbt is a tuple at that point.