Formula function (not too difficult i think)

[Jam_XD02]

Hi everyone! I am new to Python. I want to make a function like the example above. When I type the year number, it should return the result according to the formula above (use return() instead using print(). Thank you for your help .

Year 1 = x
Year 2 = Year 1 *y+x
Year 3 = Year 2*y+x
Year 4 = Year 3*y+x
.
.
.
(continue)


Eg.
Enter Year: 2
Result: xy+x

Eg.
Enter Year: 4
Result: ((xy+x)(y)+x)y+x

[buran]

not difficult indeed. What have you tried? what is x and what is y?

[Jam_XD02]

not difficult indeed. What have you tried? what is x and what is y?

x = 100 and y = 5

I have tried this, but it seems not working.

def loop(year):

  while 1 < year:
      x = 100 * 5 + 100      
      return x
  return x

if __name__=='__main__': 
  year = 2
  print(loop)

buran write Apr-09-2021, 11:00 AM:
Please, use proper tags when post code, traceback, output, etc. This time I have added tags for you.
See BBcode help for more info.

[ndc85430]

Why are you printing the function on line 10? You need to call the function, passing in the value for its parameter, year.

[jefsummers]

Also, to keep it general, loop() should have 3 parameters - year, x, and y.
You then do not decrement year so the loop will repeat infinitely.
Finally, you do not need a loop, rather exponentiation (hint, some x and y formula raised to the power of year)

[naughtyCat]

......

def func(year):
    x = 100; y = 5
    if year == 1: return x
    return (func(year-1))*y+x

for i in range(1, 5):
    print(func(i))

Output:
100
600
3100
15600

[ndc85430]

Please don't do people's homework for them.