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looping a dictionary
#2
The first line creates an empty dict and assigns it to the name job_args.

The third line is a list comprehension, a compact way of gathering the output of a looping construct in a list. The line could be "unrolled" and replaces something like this:

temp_list = []
for arg_str in args.job_args:
    temp_list.append(arg_str.split("="))
job_args_tuples = temp_list
The fourth line is similar, but it is a dict comprehension instead of a list comprehension.

temp_dict = {}
for a in job_args_tuples:
    temp_dict[a[0]] = a[1]
job_args = temp_dict
harmans14 likes this post
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Messages In This Thread
looping a dictionary - by harmans14 - Apr-11-2021, 07:15 PM
RE: looping a dictionary - by bowlofred - Apr-11-2021, 08:48 PM

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