help on else condition

[jip31]

hi
when I try to add an else condition, i have the message "(variable) else: Any"
what is the problem please?

if reponse == 'Oui' or reponse == 'oui':
     print("Super,le tirage va commencer" '!')
tirage()
else:
  quitter = input("Souhaitez-vous quitter le jeux du loto (o/n) ? ")

[deanhystad]

Indentation defines code blocks in Python. Because "tirage()" is indented the same as "if response..." it marks the start of a new code block and it's execution is not affected by the if statement. You should be getting a syntax error because the "else:" does not have a corresponding "if". When I ran you code I get this message.

Output:
  File "...\junk.py", line 4
    else:
    ^    
SyntaxError: invalid syntax

[Yoriz]

You will have a syntax error because tirage() is not intended into the if statement also your indents should be 4 spaces.

[jip31]

So does it mean that I cant use such a code or does it means I have to ident tirage()?
Because I tried to indent tirage() in the if block but it doenst works....

[perfringo]

As we don't know what tirage() does and what does 'doesn't work' mean it's very hard to provide any assistance.

But one thing you could consider writing differently:

if response.lower() == 'oui':    # covers all possible letter combinations: 'OUI', 'Oui', 'oUi' etc.

[jip31]

As we don't know what tirage() does and what does 'doesn't work' mean it's very hard to provide any assistance.

But one thing you could consider writing differently:

if response.lower() == 'oui':    # covers all possible letter combinations: 'OUI', 'Oui', 'oUi' etc.

thanks