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[solved] dataframe and read_csv
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[solved] dataframe and read_csv
#1
Aim: I would like to convert data, read with read_csv and convert it to a dataframe.
What I've tried: 1. data = pd.read_csv(...) 2. pd.DataFrame(data)
Problem: The columns are not shown in the dataframe as expected in 2 columns.


import pandas as pd
import numpy as np

from datetime import datetime, timedelta

# read data, date_parser=[0]: first column to datetime, 
data = pd.read_csv('minimal_data.csv', delimiter = ';', date_parser=[0], usecols=[0, 1], header = 0, names = ["MyColumn1","MyColumn2"]), 
   
print(data)    
    
df = pd.DataFrame(data)

print(df) 
---
MacOS 10.15.7, Jupyter notebook

Attached Files

.csv   minimal_data.csv (Size: 418 bytes / Downloads: 267)
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#2
Hello,

I.m not an expert with pandas, however:
  • data is already a dataframe.
  • drop lines 10 - 13 and all will be fine.

import pandas as pd
import numpy as np
 
from datetime import datetime, timedelta
 
# read data, date_parser=[0]: first column to datetime, 
data = pd.read_csv('minimal_data.csv', delimiter = ';', date_parser=[0], usecols=[0, 1], header = 0, names = ["MyColumn1","MyColumn2"]), 
    
print(data)    
Output:
( MyColumn1 MyColumn2 0 09.06.2021 14:35:05 100 1 09.06.2021 14:36:16 100 2 09.06.2021 14:37:26 100 3 09.06.2021 14:38:37 100 4 09.06.2021 14:39:48 100 5 09.06.2021 14:40:59 100 6 09.06.2021 14:42:10 100 7 09.06.2021 14:43:21 100 8 09.06.2021 14:44:32 100,)
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#3
Thank you. I actually need to further evaluate the data. And if I try it directly with data, I get:

data.dtypes

AttributeError: 'tuple' object has no attribute 'dtypes'
or

data.loc[data['MyColumn2'] == 0]

AttributeError: 'tuple' object has no attribute 'iloc'
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#4
(Jun-15-2021, 01:26 PM)ju21878436312 Wrote: hank you. I actually need to further evaluate the data. And if I try it directly with data, I get:
You need to get thee DataFrame out of tuple.
Here a example with some advice.
import pandas as pd
import numpy as np

# Pandas has own datateime do not need to use this
#from datetime import datetime, timedelta

# read data, date_parser=[0]: first column to datetime,
data = pd.read_csv('minimal_data.csv', delimiter = ';', date_parser=[0], usecols=[0, 1], header=0, names=["MyColumn1","MyColumn2"]),

# Get DataFrame out of tupe
df = data[0]
# Convert to datetime64
df['MyColumn1'] = pd.to_datetime(df['MyColumn1'])
print(df.dtypes)
print(df)
print('-' * 30)
print(df.loc[df['MyColumn2'] == 0])
Output:
MyColumn1 datetime64[ns] MyColumn2 int64 dtype: object MyColumn1 MyColumn2 0 2021-09-06 14:35:05 178 1 2021-09-06 14:36:16 59 2 2021-09-06 14:37:26 0 3 2021-09-06 14:38:37 0 4 2021-09-06 14:39:48 0 5 2021-09-06 14:40:59 0 6 2021-09-06 14:42:10 0 7 2021-09-06 14:43:21 0 8 2021-09-06 14:44:32 0 ------------------------------ MyColumn1 MyColumn2 2 2021-09-06 14:37:26 0 3 2021-09-06 14:38:37 0 4 2021-09-06 14:39:48 0 5 2021-09-06 14:40:59 0 6 2021-09-06 14:42:10 0 7 2021-09-06 14:43:21 0 8 2021-09-06 14:44:32 0
ju21878436312 likes this post
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#5
@snippsat: Thank you very much for the useful comments! Dance
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