ascii question

[DPaul]

In the homework section, a Cesar cypher is presented.
A string of symbols is provided:

1	SYMBOLS = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890 !?.'

But as you can see, this is far from complete on the punctuation side, thus forcing us to write code,
in case a symbol from the cypher is not found. Fine, you can do that. (e.g. comma, hyphen...)
I thought of doing this, to make list more complete and generic:

1 2	import string symbols = '  ' + string.ascii_letters + string.digits + string.punctuation

Output:
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ 

Only, the string .punctuation contains both ' and ", making the program wonder where the symbols string starts and ends.
Of course it is possible to choose and "pop" one before adding string.punctuation to symbols, but is there a better way?
(Make a list instead?)
Paul

[Gribouillis]

You can use a triple quoted string

1 2 3 4

>>> SYMBOLS = """abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~""" >>> >>> SYMBOLS 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'

Also for a better looking code, use lexical string concatenation

1 2 3

>>> SYMBOLS = ( ...     """abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789""" ...     """!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~""")

[snippsat]

1 2 3 4 5 6 7

>>> import string >>> >>> symbols = f"""{string.ascii_letters}{string.digits}{string.punctuation}""" >>> symbols 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~' >>> print(symbols) abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~

[Larz60+]

you and also use string

1 2 3 4 5

import string     SYMBOLS = f"{string.ascii_lowercase}{string.ascii_uppercase}{string.punctuation}" print(SYMBOLS)

Output:
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'

see: https://docs.python.org/3/library/string...-constants

[DPaul]

Plenty of choice.
Thanks,
Paul

[Yoriz]

And another choice.

1 2 3

import string   print("".join((string.ascii_letters, string.digits, string.punctuation)))

Output:
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~

[DPaul]

One question, 4 viable answers.
I'm
Paul

[naughtyCat]

using this \ before u want to print out strings symbol like ' or ".

1 2	symbols = 'banana \' apple' print(symbols)

Output:
banana ' apple

[perfringo]

Thread name consists ascii. So lazy person like me would do:

1 2	>>> ''.join(chr(i) for i in range(32, 127)) ' !"#$%&\'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~'

[Yoriz]

If you are not worried about the numbers being first you could use, the slice is trimming of the whitespace characters tab, linefeed, return, formfeed, and vertical tab.

1 2 3

import string   print(string.printable[:-5])

Output:
0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ 

Edit: changed the slice to 5 so it includes a space on the end