If condition not met but still running

[CreeperBob16]

I'm new to Python as a language but not coding as a whole, and I can't figure out why an if statement is running when the conditions aren't met. I'm trying to make a simple conversion tool, but no matter what the user tells it to convert to, the program always converts it to kg. Whenever I type an L to signify it needs to convert to lbs and not kg it still converts to kg. I can't figure out why it only wants to convert to kg even when it doesn't have the right conditions being met

weight = input("Weight: ")
convert = input("Convert to (K)g or (L)bs: ")

if convert == "K" or "k":
    print("Rough weight in Kg: " + str(float(weight) // 2.205))
elif convert == "L" or "l":
    print("Rough weight in Lbs: " + str(float(weight) * 2.205))

[popejose]

if convert == "K" or convert == "k":
    print("Rough weight in Kg: " + str(float(weight) // 2.205))
elif convert == "L" or convert == "l":
    print("Rough weight in Lbs: " + str(float(weight) * 2.205))

That should do it.

[ndc85430]

See, e.g. my post here for why what you've written is wrong.

[deanhystad]

I like this example.

print('K' == 'K' or 'k')
print('k' == 'K' or 'k')
print('r' == 'K' or 'k')
print('K' or 'k')

Output:
True
k
k
K

[snippsat]

If convert to upper() then no or needed as it now match both k and K.
Here a example using f-string limited to decimal places :.2f.

weight = input("Weight: ").upper()
convert = input("Convert to (K)g or (L)bs: ").upper()
if convert == "K":
    print(f"Rough weight in Kg: {float(weight) // 2.205:.2f}")
elif convert == "L":
    print(f"Rough weight in Kg: {float(weight) * 2.205:.2f}")

In need more option a more pythonic way is to use the in operator.

weight = input("Weight: ").upper()
convert = input("Convert to (K)g or (L)bs: ").upper()
if convert in ("KG", "KILO", "K"): #Like this
    print(f"Rough weight in Kg: {float(weight) // 2.205:.2f}")
elif convert == "L":
    print(f"Rough weight in Kg: {float(weight) * 2.205:.2f}")