If condition not met but still running

[CreeperBob16]

I'm new to Python as a language but not coding as a whole, and I can't figure out why an if statement is running when the conditions aren't met. I'm trying to make a simple conversion tool, but no matter what the user tells it to convert to, the program always converts it to kg. Whenever I type an L to signify it needs to convert to lbs and not kg it still converts to kg. I can't figure out why it only wants to convert to kg even when it doesn't have the right conditions being met

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weight = input("Weight: ") convert = input("Convert to (K)g or (L)bs: ")   if convert == "K" or "k":     print("Rough weight in Kg: " + str(float(weight) // 2.205)) elif convert == "L" or "l":     print("Rough weight in Lbs: " + str(float(weight) * 2.205))

[popejose]

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if convert == "K" or convert == "k":     print("Rough weight in Kg: " + str(float(weight) // 2.205)) elif convert == "L" or convert == "l":     print("Rough weight in Lbs: " + str(float(weight) * 2.205))

That should do it.

[ndc85430]

See, e.g. my post here for why what you've written is wrong.

[deanhystad]

I like this example.

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print('K' == 'K' or 'k') print('k' == 'K' or 'k') print('r' == 'K' or 'k') print('K' or 'k')

Output:
True
k
k
K

[snippsat]

If convert to upper() then no or needed as it now match both k and K.
Here a example using f-string limited to decimal places :.2f.

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weight = input("Weight: ").upper() convert = input("Convert to (K)g or (L)bs: ").upper() if convert == "K":     print(f"Rough weight in Kg: {float(weight) // 2.205:.2f}") elif convert == "L":     print(f"Rough weight in Kg: {float(weight) * 2.205:.2f}")

In need more option a more pythonic way is to use the in operator.

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weight = input("Weight: ").upper() convert = input("Convert to (K)g or (L)bs: ").upper() if convert in ("KG", "KILO", "K"): #Like this     print(f"Rough weight in Kg: {float(weight) // 2.205:.2f}") elif convert == "L":     print(f"Rough weight in Kg: {float(weight) * 2.205:.2f}")