max() and min() in Python

[coder_sw99]

Hello,

If two iterable objects are put
in the max or min function, then the sum of both iterables is calculated and the
iterable with the biggest sum will be outputted.
Thats how I understand how max() and min() works with more then one iterable object

t1 = 2,1,3
t2 = 1,3,1,5

print("Max. Value:", max(t1,t2))
print("Min. Value:", min(t1,t2))

Output:
Max. Value: (2, 1, 3)
Min. Value: (1, 3, 1, 5)

I don´t quite understand then why t1 is max and t2 is min

[Yoriz]

The tuple values are compared by the first element and then the second element etc.
with

t1 = 2,1,3
t2 = 1,3,1,5

t1 first element is larger the t2 first element

---

items = ((2, 1, 3), (1, 3, 1, 5), (2, 1, 4), (2, 0, 3), (2, 2, 4), (2, 2, 3))
print(f"Sorted: {sorted(items)}")
print(f"Max. Value: {max(items)}")
print(f"Min. Value: {min(items)}")

Output:
Sorted: [(1, 3, 1, 5), (2, 0, 3), (2, 1, 3), (2, 1, 4), (2, 2, 3), (2, 2, 4)]
Max. Value: (2, 2, 4)
Min. Value: (1, 3, 1, 5)

---

If you want the max and min of of both t1 and t2 combined you could unpack them

t1 = 2, 1, 3
t2 = 1, 3, 1, 5

print(f"Max. Value: {max(*t1,*t2)}")
print(f"Min. Value: {min(*t1,*t2)}")

Output:
Max. Value: 5
Min. Value: 1

[Gribouillis]

Tuples are compared according to lexicographic order.

[coder_sw99]

Thanks a lot!