Posts: 18
Threads: 8
Joined: Dec 2021
Dec-27-2021, 08:11 AM
(This post was last modified: Dec-27-2021, 08:11 AM by noahverner1995.)
I have the following dictionary:
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the_dictionary_list = {'Fondo': ['Oceano.png'],
'Cuerpo': ['Cuerpo_cangrejo.png'],
'Ojos': ['Antenas.png', 'Pico.png', 'Verticales.png'],
'Color': ['Amarillo.png', 'Blanco.png', 'Rojirosado.png', 'Turquesa.png', 'Verde_oscuro.png', 'Zapote.png'],
'Pinzas': ['None', 'Pinzitas.png', 'Pinzotas.png', 'Pinzota_pinzita.png'],
'Puas': ['None', 'Arena.png', 'Marron.png', 'Purpura.png', 'Verde.png']}
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And to get each possible permutation without repetition in a specific order (i.e. cartesian products) I use the following code:
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import itertools as it
AllKeysNames = ['Fondo', 'Cuerpo', 'Ojos', 'Color', 'Pinzas', 'Puas']
Combinations = list(it.product(*(the_dictionary_list[Name] for Name in AllKeysNames)))
print(f'{Combinations}')
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How can I make the above program saves each iteration to a dataframe such as it throws an output like this one:
Output: Index | Permutations | FilePermutations
0 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+None
1 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+Arena.png
2 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+Marron.png
.
.
.
The information within the Permutations column will remain constant, and the dataframe would ended up with an index length of 359.
Posts: 18
Threads: 8
Joined: Dec 2021
(Dec-27-2021, 08:11 AM)noahverner1995 Wrote: I have the following dictionary:
1 2 3 4 5 6 |
the_dictionary_list = {'Fondo': ['Oceano.png'],
'Cuerpo': ['Cuerpo_cangrejo.png'],
'Ojos': ['Antenas.png', 'Pico.png', 'Verticales.png'],
'Color': ['Amarillo.png', 'Blanco.png', 'Rojirosado.png', 'Turquesa.png', 'Verde_oscuro.png', 'Zapote.png'],
'Pinzas': ['None', 'Pinzitas.png', 'Pinzotas.png', 'Pinzota_pinzita.png'],
'Puas': ['None', 'Arena.png', 'Marron.png', 'Purpura.png', 'Verde.png']}
|
And to get each possible permutation without repetition in a specific order (i.e. cartesian products) I use the following code:
1 2 3 4 5 |
import itertools as it
AllKeysNames = ['Fondo', 'Cuerpo', 'Ojos', 'Color', 'Pinzas', 'Puas']
Combinations = list(it.product(*(the_dictionary_list[Name] for Name in AllKeysNames)))
print(f'{Combinations}')
|
How can I make the above program saves each iteration to a dataframe such as it throws an output like this one:
Output: Index | Permutations | FilePermutations
0 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+None
1 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+Arena.png
2 |Fondo+Cuerpo+Ojos+Color+Pinzas+Puas|Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Amarillo.png+None+Marron.png
.
.
.
The information within the Permutations column will remain constant, and the dataframe would ended up with an index length of 359.
Got it:
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new = ['+'.join(x) for x in it.product(*(the_dictionary_list[Name] for Name in AllKeysNames))]
df = pd.DataFrame({'Permutations':"+".join(AllKeysNames), 'FilePermutations':new})
print(df)
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Output: Permutations \
0 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
1 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
2 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
3 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
4 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
.. ...
355 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
356 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
357 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
358 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
359 Fondo+Cuerpo+Ojos+Color+Pinzas+Puas
FilePermutations
0 Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Ama...
1 Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Ama...
2 Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Ama...
3 Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Ama...
4 Oceano.png+Cuerpo_cangrejo.png+Antenas.png+Ama...
.. ...
355 Oceano.png+Cuerpo_cangrejo.png+Verticales.png+...
356 Oceano.png+Cuerpo_cangrejo.png+Verticales.png+...
357 Oceano.png+Cuerpo_cangrejo.png+Verticales.png+...
358 Oceano.png+Cuerpo_cangrejo.png+Verticales.png+...
359 Oceano.png+Cuerpo_cangrejo.png+Verticales.png+...
[360 rows x 2 columns]
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