Find if chain of characters or number

[Frankduc]

Hello,

Try to determine if its a chain of characters or numbers.

1 2 3 4 5 6 7 8 9

mot = input("input something:  ")   for num in mot:     if num not in "0123456789":        print("its ccharacters")     else:        print("its number")

Output:
input something:  jkl
its ccharacters
its ccharacters
its ccharacters

The problem it is checking every characters one by one and i just want to tell for the whole word.

Dont use isnumber or digit gadget.

TY

[menator01]

Might try this. If the string has numbers and letters ir will return as a string.

1 2 3 4 5 6 7 8 9 10

while True:     prompt = input('input: ')     if prompt == 'q':         break       try:         if int(prompt):             print('numbers')     except ValueError:         print('letters')

Output:
input: 6523
numbers
input: string
letters
input: number1
letters
input: number 2
letters
input: q

[deanhystad]

You can use "isnumeric()"

1	print('123'.isnumeric(), 'abc'.isnumeric(), '1.23'.isnumeric())

Output:
True False False

You can use a regular expression.

1 2 3 4 5 6 7

import re   is_int = re.compile(r'^-?\d*$') print(is_int.match('123') is not None) print(is_int.match('abc') is not None) print(is_int.match('1.23') is not None) print(is_int.match('-123') is not None)

Output:
True
False
False
True

As menator01 recommends, conversion (you probably want the numeric value anyway) and catching the exception is likely the best solution. Use float() instead of int() if you want to allow decimals.

[menator01]

Updated to include floats

1 2 3 4 5 6 7 8 9 10 11 12 13 14

while True:     prompt = input('input: ')     if prompt == 'q':         break       try:         int(prompt)         print('number')     except ValueError:         try:             float(prompt)             print('float')         except ValueError:             print('letters')

Output:
input: 3259    
number         
input: 5.33    
float          
input: text    
letters        
input: 5text   
letters        

[Frankduc]

Hello guys.

Sorry for the late reply, i had courses yesterday since i started in AI.
The book was asking for brute force approach. You cannot use try, except, import or isnumeric.

It is tempting i admit to use gadget but forbidden.

I came up with that solution in my bed at one am. Sorry its in french.

1 2 3 4 5 6 7 8 9 10

mot = input("Une chaîne de charactères svp!:  ") count = 0   for num in mot:     if num in "0123456789":        count += 1        if count == len(mot):           print("Il s'agit d'un nombre entier de", count, "chiffres")     else:       print("Il s'agit d'une chaîne de caractères.")

Output:
Une chaîne de charactères svp!:  4789
Il s'agit d'un nombre entier de 4 chiffres

Thanks guys for the help. I will take in note some of your suggestion.