Is there a better way

[Able98]

Is there a better way of doing this?

1 2	f = open(somename.dat) print ("{0}" .format(f.name) + ".txt")

output is "somename.dat.txt"

Also want just the file name without the "dat" extension so output will be:

"somename.txt"

[snippsat]

I don't see the point,do you also have file on disk named somename.txt.
Or just want to rename the file?

1 2 3

>>> f = open('somename.dat') >>> print ('{}.txt'.format(f.name.split('.')[0])) somename.txt

[nilamo]

Pathlib to the rescue!

1 2 3 4 5

import pathlib as path   with open("somefile.txt") as f:     info = path.Path(f.name)     print(info.stem) # "somefile"