Why is the if construct not calculating correctly?

[egemynet]

        bars = exchange.fetch_ohlcv(symbol, timeframe=zamanAraligi, since=None, limit=500)
        df = pd.DataFrame(bars, columns=["timestamp", "open", "high", "low", "close", "volume"])

        #ema control
        e8 = ta.ma("ema", df.close, length=8)
        e13 = ta.ma('ema', df.close, length=13)
        e21 = ta.ma('ema', df.close, length=21)
        e55 = ta.ma('ema', df.close, length=55)

        total = 0
        if any(e8 > e13):
            total += 1
        else:
            total -= 1

        if any(e13 > e21):
            total += 1
        else:
            total -= 1

        if any(e21 > e55):
            total += 1
        else:
            total -= 1

        print("Ema 8  =", e8)
        print("Ema 13 =", e13)
        print("Ema 21 =", e21)
        print("Ema 55 =", e55)

        print("rating =", total)

Of course, I'm waiting for help, sorry for the delay. I had to go out for an unexpected reason, the final code is by, if I don't use "any" it gives the error I mentioned, when I use it, it doesn't return the correct result no matter what I do.

[deanhystad]

Do you know what any does?

import numpy as np
a = np.array([1, 1, 1])
b = np.array([1000, 1000, 0])

print(any(a > b))

Output:
True

Because one element in a is greater than the corresponding element in b, any(a > b) is True. Is that the comparison you want to make?

I suggested you compare

if e8[-1] > e13[-1]:

because you are printing out e8[-1] and e13[-1] and using that in your argument that the if statement is producing the wrong result. For some reason you instead compared:

if e8 > e13:

Which is an error because Python does not know how you want to compare the two arrays.

I don't think comparing the very last element in the array is a good way to compare two arrays, but at least the results would align with what you think they should be. Maybe you should compare the mean?

import numpy as np
a = np.array([1, 1, 1])
b = np.array([1000, 1000, 0])

print("any a > b", any(a > b))
print("last a > b", a[-1] > b[-1])
print("average a > b", a.mean() > b.mean())

Output:
any a > b True
last a > b True
average a > b False

Or maybe there are other characteristics that are more important.