##### How to find the second lowest element in the list?
 How to find the second lowest element in the list? Anonymous Unladen Swallow Posts: 1 Threads: 1 Joined: May 2022 Reputation: May-31-2022, 12:22 PM I have a list of students and I have to print the names of students who have scored second lowest. students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]] The lowest grade of belongs to Tina. The second lowest grade of belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line. I am extremely new to python so I have coded as below - ``` studList = [] for i in range(int(input())): name = input() score = float(input()) studList.append([name,score]) studList = sorted(studList, key = lambda x: x[1], reverse = True) print(studList) ```I have done till the point that I now have a sorted list but now I am not sure I do I extract the second lowest scorer's names. Reply DeaD_EyE Da Bishop Posts: 1,878 Threads: 8 Joined: May 2017 Reputation: May-31-2022, 01:49 PM (This post was last modified: May-31-2022, 02:43 PM by DeaD_EyE.) use operator.itemgetter or lambda for the key function sort your list reversed (big numbers first) with the key function use the index `-2` to access the second-smallest element ```from operator import itemgetter values = [('A', 4), ('B', 3), ('C', 1), ('D', 6), ('E', 1), ('F', -10), ('G', -20)] # the second smallest number is -10 name_getter = itemgetter(0) value_getter = itemgetter(1) # itemgetter is useful as a key function for sorting # this prevents the use of lambda sorted_values = sorted(values, reverse=True, key=value_getter) # btw, If you had chosen (value, name), then the key function is not required. # # get both, name and value result = sorted_values[-2] print(result) # name_getter return index 0 from result print(name_getter(result)) # or print(result[0])``` Almost dead, but too lazy to die: https://sourceserver.info All humans together. We don't need politicians! Reply Coricoco_fr Silly Frenchman Posts: 24 Threads: 0 Joined: Mar 2022 Reputation: May-31-2022, 01:58 PM (This post was last modified: May-31-2022, 08:45 PM by Coricoco_fr.) Hello, ```>>> students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]] >>> studList = [student[0] for student in sorted(students, key = lambda x: x[1], reverse = True)] >>> print(studList) ['Akriti', 'Harsh', 'Harry', 'Berry', 'Tina'] >>>```édit: sorry I speak Python but I don't speak English (I just read it a little). If I express myself badly, please blame the translator^^. Reply Larz60+ aetate et sapientia Posts: 11,483 Threads: 437 Joined: Sep 2016 Reputation: May-31-2022, 01:58 PM ```students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]] sorted_students = sorted(students, key=lambda x:x[1], reverse=True) print(f"Second lowest = {sorted_students[-2]}", end = '') if sorted_students[-3][1] == sorted_students[-2][1]: print(f" and {sorted_students[-3]}") else: print()```results: ``Output:Second lowest = ['Berry', 37.21] and ['Harry', 37.21]`` Reply

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