Concatinating two strings to make a variable

[bencouve]

I want to concatenate two strings so that they match  predefined variables which can load them into a list, something like this ..

k = []
i0 = 'This'
i1 = 'is'
i2 = 'the'
i3 = 'string'
for x in range(3):
    k.append('i' + str(x))

Result

Output:
['i0', 'i1', 'i2', 'i3']

Needed result

Output:
['This', 'is', 'my', 'string']

A simple one to start with I know but have tried a few different ways of doing this but have failed. Thanks in advance.

[buran]

Not sure what the point of all this is, but for sake of exercise you can do this by using locals() built-in function

# python3

i0 = 'This'
i1 = 'is'
i2 = 'the'
i3 = 'string'
# approach1
k = []
for x in range(4):
    k.append(locals()['i{}'.format(x)])
print(k)

# approach2 list comprehension
another_k = [locals()['i{}'.format(x)] for x in range(4)]
print(another_k)

Output:
['This', 'is', 'the', 'string']
['This', 'is', 'the', 'string']
>>>

Also, note the change I made to range

[bencouve]

Perfect! Thanks ...

and ok

first post

[buran]

Perfect! Thanks ...

in any case, I suspect design flaw

[DeaD_EyE]

Perfect! Thanks ...

and ok

first post

Please don't do this. You're using the wrong data structure. Maybe you want to have a dict:

data = {'i0': 'This', 'i1': 'is', 'i2': 'the', 'i3': 'string'}

# direct access
print(data['i0'])

# iterating over values
# unordered

for value in data.values():
   print(value)

# sorted access
# sorted sorts by first element, if the the yielded element is a list/tuple
for key, value in sorted(data.items()):
   print(value)

# or preserve the order:
from collections import OrderedDict
data = [('i0', 'This'), ('i1', 'is'), ('i2', 'the'), ('i3', 'string')]
ordered_dict = OrderedDict(data)

for value in ordered_dict.values():
   print(value)

Since Python 3.6 dicts preserve the order, but we should not rely on it. Maybe with next version they guarantee it.
Currently it's just an implementation detail.

[Ofnuts]

Perfect! Thanks ...

and ok

first post

Please don't do this. You're using the wrong data structure. Maybe you want to have a dict:

data = {'i0': 'This', 'i1': 'is', 'i2': 'the', 'i3': 'string'}

# direct access
print(data['i0'])

# iterating over values
# unordered

for value in data.values():
   print(value)

# sorted access
# sorted sorts by first element, if the the yielded element is a list/tuple
for key, value in sorted(data.items()):
   print(value)

# or preserve the order:
from collections import OrderedDict
data = [('i0', 'This'), ('i1', 'is'), ('i2', 'the'), ('i3', 'string')]
ordered_dict = OrderedDict(data)

for value in ordered_dict.values():
   print(value)

Since Python 3.6 dicts preserve the order, but we should not rely on it. Maybe with next version they guarantee it.
Currently it's just an implementation detail.

... or even simpler, an array:

i = [ 'This','is','the', 'string' ]  # Stylistically `i` is a bad name for an array

# direct access
print(i[0])

# iterating over value (always ordered)
for value in i:
   print(value)