(off) and (on) sequence

[AlexPython]

Hello. What I trying to do is a sequence of nodes that will be connected to each other and pass power if they are on.
I tried doing it as if I was doing the battleship game but it kinda did not work.

board = []
for i in range(1):
    board.append([])
    for j in range(10):
        board[i].append([])
        for k in range(10):
            board[i][j].append('-')

for level in board:
    for row in level:
        print(row)

above is the grid i was using.

I want to create a 10x10 grid that will randomly turn each of the outside dots into a 1 or a 0 in a sequence and when one of them turns into a 0 all the other dots should turn into a 0.
It should look like this:

Anyone who can point me in the right direction, I appreciate it.

[deanhystad]

That is a lot of for loops.

This will create a row of 10 dashes.

row = [['-'] * 10]

This will create board with 10 rows

board = [['-'] * 10 for _ in range(10)]

And this will print the board

print('\n'.join(map(str, board)))

I don't understand what you mean by this and your picture:

I want to create a 10x10 grid that will randomly turn each of the outside dots into a 1 or a 0 in a sequence and when one of them turns into a 0 all the other dots should turn into a 0.

Do you mean something like this where put zeros in row 2 and ones in column 3?

Output:
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['0', '0', '0', 1, '0', '0', '0', '0', '0', '0']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']
['-', '-', '-', 1, '-', '-', '-', '-', '-', '-']

[AlexPython]

no. I mean something like this

The space in the middle of the grid can be ignore i just put it so it looks better, the important is the outside (. or -) those are the ones that will change into a 1 or a 0.

---

Each node(it can be a (.) or a (-) whatever you prefer) connects to the next node and allows the power to flow to that next node. You can make the first one always be 1 so it would pass the energy to the second one and then randomly the program will decide if the next one is a 1 or a 0. if it is a 0 then the program will finish and assign 0 to all other nodes because the power supply was cut off.

[perfringo]

those are the ones that will change into a 1 or a 0.

What are default values of "those"?

[AlexPython]

those are the ones that will change into a 1 or a 0.

What are default values of "those"?

The default value of the first one should be 1 all the others will vary depending on the previous value. For example the first will always be 1 now because the first one is 1 then the second can be a 1 or a 0, let said that the second note was also a 1, the third note will randomly choose for 1 or 0 similar to the second node only because the previous result was a 1 if the previous result was a 0 then all the future nodes will also be a 0 automatically.

5-nodes
result: 5 different results (1-1-1-0-0) - (1-0-0-0-0) - (1-1-0-0-0) - (1-1-1-1-0) - (1-1-1-1-1)

[Yoriz]

This will create an iterator that always starts with 1, it will then randomly choose if it's a 0 or 1, once it is a 0 it will always be 0 until a new version is called.

import random


def on_till_randomly_off(count):
    if not count:
        return
    current_count = 0
    while True:
        if current_count == count:
            return
        yield 1
        current_count += 1
        if random.randint(0, 1):
            break
    while True:
        if current_count == count:
            return
        yield 0
        current_count += 1


print("-".join(str(state) for state in on_till_randomly_off(5)))
print("-".join(str(state) for state in on_till_randomly_off(5)))
print("-".join(str(state) for state in on_till_randomly_off(5)))
print("-".join(str(state) for state in on_till_randomly_off(5)))
print("-".join(str(state) for state in on_till_randomly_off(5)))

Output:
1-0-0-0-0
1-1-1-0-0
1-0-0-0-0
1-1-1-1-1
1-0-0-0-0

---

Shortened version

def on_till_randomly_off2(count):
    state = 1
    for _ in range(count):
        yield state
        if state:
            state = random.randint(0, 1)

[AlexPython]

Thank you buddy.