i guess i don't really understand locals

[Skaperen]

def funa():
    print('started funa')
    foo = 'bar'
    def funb():
        print('started funb')
        print('locals() =',repr(locals()))
        print('locals() has "foo":','foo' in locals())
        print('end funb')
    def func():
        print('started func')
        print('locals() =',repr(locals()))
        print('locals() has "foo":','foo' in locals())
        print('foo =',repr(foo))
        print('locals() =',repr(locals()))
        print('locals() has "foo":','foo' in locals())
        print('end func')
        return
    funb()
    func()
    print('end funa')
    return
funa()

then when i run it i get:

Output:
started funa
started funb
locals() = {}
locals() has "foo": False
end funb
started func
locals() = {'foo': 'bar'}
locals() has "foo": True
foo = 'bar'
locals() = {'foo': 'bar'}
locals() has "foo": True
end func
end funa

when funb() or func() is called, they may or may not access the callers locals. this seems to depend on the compiler seeing it or something. this could break accessing locals()[name] where name refers to "foo". i think i need to play with it more to see what it really does.