Extract file only (without a directory it is in) from ZIPIP

[tester_V]

Greetings!
I'd like to extract files only, without the directories they are in, in the ZIP.
I wrote a small script but it extracts files with the directories.
Could you help me with this, please?

from zipfile import ZipFile
zp_dr   = 'C:\\02\\ZP_Files\\my.zip
dir_out = 'C:\\02\\ZP_Out

with zipfile.ZipFile(zp_dr) as zz:
       for file in zz.namelist():
            if 'Trace' in file :
                print (f"ZIP Item : {file}")
                zz.extract(file,dr_out)

Any help is appreciated.
Thank you!

[deanhystad]

Use Zipfile.extractall(). I think it will do exactly what you want.

If you only want to extract files that match some kind of pattern, making extractall() a poor fit, you can specify an absolute path. This program extracts png files and puts them in my test folder.

from zipfile import ZipFile
from pathlib import Path

with ZipFile('games.zip', 'r') as zip:
    for file in zip.namelist():
        if Path(file).suffix == ".png":
            zip.extract(file, f'test/{Path(file).name}')