Phyton Opening files on windows C: pc

[EddieG]

Hello,
A newbie here. I am into my lesson opening files on Python. The lesson is to copy a poem on the text editor (note++) . I saved the poem on my desktop for easy locating when required.

Actual Windows path
(C:\User\hp\desktop\Poem.txt)

However following the open() function example to pass the file into a variable as object.
poem=open("/home/pi/Document/Poen.txt")

results in a error no file found.

using the textbook example to open the file as
poem=open("C:/User/hp/desktop/Poem.txt")

When the code was written in the shell, pressing enter returns a file not error:

Python Version 3.11.2

What is the correct way to tell Python where to find the file in this situation. A spoon fed code (written full code) using the windows C: path answer is most welcome.

Thank you for your response in advance.

[buran]

For start, Windows has Users folder (plural), not User. Also is user really hp?

So, It should be
r'C:\Users\<user name>\Desktop\Poem.txt'
or
'C:/Users/<user name>/Desktop/Poem.txt'

[EddieG]

For start, Windows has Users folder (plural), not User. Also is user really hp?

So, It should be
r'C:\Users\<user name>\Desktop\Poem.txt'
or
'C:/Users/<user name>/Desktop/Poem.txt'

YES!!!,
Thanks a lot Buran my man... The example is using ("....") instead of the ('...")
and here is the screen shot of the code.    

[buran]

the syntax error is because you miss closing quote for the filename string