Extracting Version Number from a String

[britesc]

Hi,
I would like to be able to extract the version number (nimbers and ,) from a string.
I can get the result but only if I use 1 type of delimeter
I have noticed that sometimes the delimeter changes so would like to have multiple delimeters options.
For example

1 2 3 4 5

import re text = 'mawk/kinetic,now 1.3.4.20200120-3.1 amd64 [installed,automatic]' m = re.search(',now (.+?)-', text)   print(m)

Output:
<re.Match object; span=(12, 32), match=',now 1.3.4.20200120-'>

1	print(m.group(0)

Output:
,now 1.3.4.20200120-

1	print(m.group(1))

Output:
1.3.4.20200120

In this case m.group(0) contains the answer I need as the delimiter was - but sometimes it can be a + or : as the final delimeter
Equally the first delimeter might be ,now 1:

For info the string is generated by apt list --installed | grep -i mawk (in this case)

So I am getting in a bit of a pickle as I know I should be able to have multiple start delimeters and multiple end delimters,
I assume there must be a simpler way of doing this rather than a series of if statements searching to see what is the start and end delimeter in a string and then calling the correct re.search code.
Regex is really powerfull and a language unto itself but I've not got much spare capacity in my onbaord mental ROM anymore.
Any advice gratefully received.
Thanks and kind regards,
jB

buran write Apr-05-2023, 10:11 AM:
Please, use proper tags when post code, traceback, output, etc. This time I have added tags for you.
See BBcode help for more info.

[ibreeden]

In this case m.group(0) contains the answer I need as the delimiter was - but sometimes it can be a + or : as the final delimeter

Then you should use:

1	m = re.search(',now (.+?)[-+:]', text)

Does that give the results you need?

[britesc]

Sorry for the delayed response. Not very well.
I have managed to use your code with a bit extra to achieve what I required.
Thank you very much.