to find in dictionary given parameter 'name' and to output position

[Pedroski55]

My Ergebnis is a list of dictionaries.

Assuming there is a result, you get the list Ergebnis, for a name like Swensonl. Each element in the list is dictionary.

Ergebnis = findName(person)
if not Ergebnis == 'Nix da!':
    # Ergebnis is a list, walk through it
    for E in Ergebnis:
        print(E)

I get this output when I enter the surname Swenson:

Output:
{'vorname': 'Thom', 'name': 'Swenson', 'adress': 'bethastr. 37'}
{'vorname': 'Dumb', 'name': 'Swenson', 'address': 'Gottlobstr. 99'}

You could do that like this:

# Ergebnis is a list of dictionaries
if not Ergebnis == 'Nix da!':
     # E is a dictionary
     for E in Ergebnis:
          for key in E.keys():
               print('key is', key, 'value is', E[key])

Your searchName(telefonbook, name) function works but returns a dictionary of dictionaries, if the surname is present more than 1 time, as in my telefonbook.

def searchName(telefonbook, name):
     """Durchsucht ein Adressbuch nach einem Namen."""   
     results = {}
    # item is a tuple of (key, value) 
     for item in telefonbook.items():
         person = item[1]
         if name in person.values():
             results[item[0]] = person
     return results

So then do:

Resultat = searchName(telefonbook, name)

for key in Resultat.keys():
     print('key is', key, 'data is', Resultat[key])

Wer suchet, der findet!!