working directory if using windows path-variable

[chitarup]

Hello,

if have a Python-script in, let's say

d:\script\myScript.py

I add this to the windows path variable:

PATH="...;d:\script;..."

Then I open a shell at d:\working. When I invoke the script with

d:\working>myScript.py

how can I get the directory from which I invoke the script, so d:\working in this case.
Commands like os.getcwd() only returns the script directory d:\script

Any Ideas?

Thanks
Stephan

[deanhystad]

When open a shell and run this program:

import os

print(os.getcwd())

It prints the name of path of the directory open in the shell, not the location of the program. For example, I open a CMD shell in "u:" and type

Output:
u:\>C:\Users\...\python\sandbox test.py
u:\

u:\>

Can you post your program?

[chitarup]

Oh dear...

Yes, you are right. It's working this way.
I added

os.chdir(os.path.join(os.path.dirname(os.path.abspath(__file__)), './'))

so that it works out of visual studio code...

Thank you!!!