Python2 to Python3 translation - .keys()

[20salmon]

Hi,

I'm trying to follow the code in a machine learning textbook. Unfortunately, the code is written in Python2, and I'm using IPython via neovim, so I have to use Python 3.

The full code can be found here.

The code won't run in Python3 without some adjustments to the printTree() function.

Original:

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def printTree(self,tree,name):     if type(tree) == dict:         print name, tree.keys()[0]         for item in tree.values()[0].keys():             print name, item             self.printTree(tree.values()[0][item], name + "\t")     else:         print name, "\t->\t", tree

My edits:

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def printTree(self,tree,name):     if type(tree) == dict:         print(name, list(tree.keys())[0])         for item in list(list(tree.values())[0].keys()):             print(name, item)     else:         print(name, "\t->\t", tree)

Alas, I still get an error when I run the code:

Output:
    
    154         def printTree(self,tree,name):
    155                 if type(tree) == dict:
--> 156                         print(name, list(tree.keys())[0])
    157                         for item in list(list(tree.values())[0].keys()):
    158                                 print(name, item)

TypeError: 'dict_keys' object does not support indexing

The puzzling thing is that I don't get the indexing error if I run the same code outside of a function. I am at a bit of a loss with how to resolve this.

[metulburr]

dict.keys returns a view not a list in python3.x
http://btmiller.com/2015/04/13/get-list-...and-3.html

You shoudl also use isinstance instead of type()