Extracting numbers

[Ronnie]

print("Line ", linenr, ": ", match[1], sep='')

I typed the following and received the "SyntaxError: invalid syntax", with the '=' sign highlighted in red in the line print("Line", liner, ":", match[1], sep='')

"
>>> pattern = re.compile(r"tel:\s*?\+44\s*?(\d{10,10})")
>>> with open ('phone_log.txt') as in_file:
for linenr, line in enumerate(in_file):
match = re.search(pattern, line, re.X)
if match:
print("Line", liner, ":", match[1], sep='')

SyntaxError: invalid syntax
>>> "

[heiner55]

Then remove sep=''':

print("Line ", linenr, ": ", match[1])

[Ronnie]

Then remove sep=''':

print("Line ", linenr, ": ", match[1])

I tried doing this earlier but received the following :

>>> with open ('phone_log.txt') as in_file:
for linenr, line in enumerate(in_file):
match = re.search(pattern, line, re.X)
if match:
print("Line ", linenr, ": ", match[1])



Traceback (most recent call last):
File "<pyshell#20>", line 3, in <module>
match = re.search(pattern, line, re.X)
File "C:\Python27\lib\re.py", line 142, in search
return _compile(pattern, flags).search(string)
File "C:\Python27\lib\re.py", line 235, in _compile
raise ValueError('Cannot process flags argument with a compiled pattern')
ValueError: Cannot process flags argument with a compiled pattern

[heiner55]

My sample runs with Python 3.6 (not with Python 2.7).

Uninstall your Python 2.7 and install Python 3.6:
https://www.python.org/ftp/python/3.6.3/...-3.6.3.exe

As a new beginner you use Python 3.6.

---

This code runs with Python 3.6 or Python 2.7:

#!/usr/bin/python3
import re

pattern = r"""
    tel:       # tel:
    \s*?       # maybe some spaces
    \+44       # +44
    \s*?       # maybe some spaces
   (\d{10,10}) # 10 digits
"""

with open ('phone_log.txt') as in_file:
    for linenr, line in enumerate(in_file):
        match = re.search(pattern, line, re.X)
        if match:
            print("Line %d: %s" % (linenr, match.group(1)))

[Ronnie]

My sample runs with Python 3.6 (not with Python 2.7).

Uninstall your Python 2.7 and install Python 3.6:
https://www.python.org/ftp/python/3.6.3/...-3.6.3.exe

As a new beginner you use Python 3.6.

---

This code runs with Python 3.6 or Python 2.7:

#!/usr/bin/python3
import re

pattern = r"""
    tel:       # tel:
    \s*?       # maybe some spaces
    \+44       # +44
    \s*?       # maybe some spaces
   (\d{10,10}) # 10 digits
"""

with open ('phone_log.txt') as in_file:
    for linenr, line in enumerate(in_file):
        match = re.search(pattern, line, re.X)
        if match:
            print("Line %d: %s" % (linenr, match.group(1)))

Thanks mate, I've done that now..
But still getting an error, I get the following:

>>> import re
>>> pattern=re.compile(r'''tel:\s*?\+44\s*?(\d{10,10})''')
>>> with open ('phone_log.txt') as in_file:
for linenr, line in enumerate(in_file):
match = re.search(pattern, line, re.X)
if match:
print("Line ", linenr, ": ", match[1])


Traceback (most recent call last):
File "<pyshell#11>", line 3, in <module>
match = re.search(pattern, line, re.X)
File "C:\Users\Ronnie\AppData\Local\Programs\Python\Python36-32\lib\re.py", line 182, in search
return _compile(pattern, flags).search(string)
File "C:\Users\Ronnie\AppData\Local\Programs\Python\Python36-32\lib\re.py", line 297, in _compile
"cannot process flags argument with a compiled pattern")
ValueError: cannot process flags argument with a compiled pattern

I was wondering how I can get rid of this?

[heiner55]

Your program is not the same as mine.
Paste my sample and run it.

#!/usr/bin/python3
import re
 
pattern = r"""
    tel:       # tel:
    \s*?       # maybe some spaces
    \+44       # +44
    \s*?       # maybe some spaces
   (\d{10,10}) # 10 digits
"""
 
with open ('phone_log.txt') as in_file:
    for linenr, line in enumerate(in_file):
        match = re.search(pattern, line, re.X)
        if match:
            print("Line %d: %s" % (linenr, match.group(1)))
#done

[Ronnie]

Your program is not the same as mine.
Paste my sample and run it.

#!/usr/bin/python3
import re
 
pattern = r"""
    tel:       # tel:
    \s*?       # maybe some spaces
    \+44       # +44
    \s*?       # maybe some spaces
   (\d{10,10}) # 10 digits
"""
 
with open ('phone_log.txt') as in_file:
    for linenr, line in enumerate(in_file):
        match = re.search(pattern, line, re.X)
        if match:
            print("Line %d: %s" % (linenr, match.group(1)))
#done

So I should copy:

#!/usr/bin/python3
import re

pattern = r"""
tel: # tel:
\s*? # maybe some spaces
\+44 # +44
\s*? # maybe some spaces
(\d{10,10}) # 10 digits
"""

with open ('phone_log.txt') as in_file:
for linenr, line in enumerate(in_file):
match = re.search(pattern, line, re.X)
if match:
print("Line %d: %s" % (linenr, match.group(1)))
#done
into my shell and then run it?
and what run option do i select, since there is
- run python
- run shell

---

and is the re.compile needed at all? since that is missing

[heiner55]

You should copy it into a file (sample.py).
Then open IDLE
Then Menu->File->Open->sample.py
A new window is open.
Then F5 or Run-> Run Module

---

Or open a cmd-Window and start:  python.exe sample.py
(assuming python.exe is in PATH)

[snippsat]

Ronnie you got information how to use BBcode tag in first post.
Use code tags,more posts without will not be tolerated.