List comprehension, I think(?)

[zykbee]

Hey guys. When I run this, it properly writes to a new text file any line of the "full" list that doesn't have a corresponding line in the "emit" list. Unfortunately, if the entries aren't exact, it falters. Can anyone assist me in how i would go about removing any line in the "full" list that has any of the corresponding strings in the "emit" list?

        full = [hi, turtle, hello, [email protected], bye(hhhh), etc ...] ### actual program has a lot more entrees
        emit = [hi, howdy, bye, etc ...] ###Actual program has a lot more entrees
        ### what i want = [hello,turtle etc...]
        ### what i get = [hello, turtle, [email protected], bye(hhh), etc ...]      


        
        new_list = []
        for item in full:
            if item in (emit):
                new_list.append(item)
        item_list = new_list
        f = open("test.txt", "w")
        f.write(("\n".join(map(lambda x: str(x), new_list))))
        f.close()

[buran]

list1 = ['alfa', 'bravo', 'charlie',  'delta', 'foxtrot']
list2 = ['alfa', 'charlie', 'echo']

# using comprehension
lists3 = [item for item in list1 if item in list2]
print(list3)

# using built-in filter()
list4 = list(filter(lambda w: w in list2, list1)) # you may skip converting to list if not neccessary
print(list4)

#if all elements in list1 are unique and order in result is not important:
set5 = set(list1) & set(list2) # you may want to convert it to list
print(set5)

[zykbee]

Thanks for your assistance, but none of your solutions are working. I am trying to emit all the strings from the 'emit list'. This is what I got instead:

FULL LIST ===[['[email protected]'], ['Cindy'], ['Blaire'], ['Chuck'], ['Sandy'], ['Bill'], ['Tuck'], ['Smith']]
EMIT LIST === [['Ann'], ['Cindy'], ['Blaire'], ['Bill'], ['Tuck'], ['Smith']]
YOUR SOLUTIONS == [['Cindy'], ['Blaire'], ['Bill'], ['Tuck'], ['Smith']]
WHAT I WANT == [Chuck] [Sandy]
BEFORE I WAS GETTING [[email protected]], [chuck] [sandy]

[buran]

Sorry, I misunderstood you - that you want the opposite. Adjust my example accordingly - use not in list2 instead of in list2
also, it looks like your 'previous' output was correct.

[zykbee]

This still arrives me upon the same dilemma as where I began. --- It's working w/o error, but still gives me ["[email protected]], [sandy], [chuck] when I run it --- I want it to just show Sandy and Chuck, because the name "Ann" is on a single line in the "emit" list. Am I explaining this, okay?

[buran]

Am I explaining this, okay?

not very well, obviously

Is it correct to assume that these as lists of single-element lists? Or it is possible to have multi-element sub-lists? will 'Ann' for example will always be in the start of the string?, etc..

[zykbee]

No. Ann will not always be at the start of the string. I want it to remove 'Ann' (and the string) no matter where it is in the list. For instance, this is what i want:

list1= [hi], [bye], [ann], [[email protected]], [HHHannHHH] ---- old list
list 2=[ann] [apple] -------emitted words
list 3 = [hi], [bye] --- new list

AND YES, all single element list.

[buran]

list1 = [['[email protected]'], ['Cindy'], ['Blaire'], ['Chuck'], ['Sandy'], ['Bill'], ['Tuck'], ['Smith'], ['HHHannHHH']]
list2 =  [['Ann'], ['Cindy'], ['Blaire'], ['Bill'], ['Tuck'], ['Smith']]

# using comprehension
list3 = [item for item in list1 if all(item2[0].lower() not in item[0].lower() for item2 in list2)]
print(list3)

[buran]

As a side note, a more pythonic (readable) would be to define separate function
 

list1 = [['[email protected]'], ['Cindy'], ['Blaire'], ['Chuck'], ['Sandy'], ['Bill'], ['Tuck'], ['Smith'], ['HHHannHHH']]
list2 =  [['Ann'], ['Cindy'], ['Blaire'], ['Bill'], ['Tuck'], ['Smith']]


def validate_item(item, check_list):
    return all(check_item[0].lower() not in item[0].lower() for check_item in check_list)
# using comprehension
list3 = [item for item in list1 if validate_item(item, list2)]
print(list3)

from functools import partial
validator =  partial(validate_item, check_list=list2)
# using built-in filter()
list4 = list(filter(validator, list1)) # you may skip converting to list if not neccessary
print(list4)

[zykbee]

YOU'RE INCREDIBLE! Thank You! If you have the chance, can you give me a quick rundown of what this did? --- all(item2[0].lower() not in item[0].lower() ---