int to hex

[pythonper]

Hello,
I am trying to convert and array of ints to hexadecimal numbers with the format as b'\x50\x15\'
When I use the struct.pack(">H", int) most numbers looks ok, but some get turned into ascii characters..
For example the int value 3360 becomes b' \r' and not b'\x0d\x20'

Another example:

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import struct minnepls=struct.pack(">i", 20500) print(minnepls)

Output:
b'\x00\x00P\x14'

Is there any way to get this to the format b'\x50\x15\x00'?
I'm using a assert len(thisvalue) which is failing on these values.

Any tips would be appreciated!

-Per

[Larz60+]

Use a format statement

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>>> minnepls = 1234 >>> print("minnepls Hex: {0:x}".format(minnepls)) minnepls Hex: 4d2 >>> print("minnepls Octal: {0:o}".format(minnepls)) minnepls Octal: 2322 >>> print("minnepls Decimal: {0:}".format(minnepls)) minnepls Decimal: 1234 >>>

Or if using python 3.6+:

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>>> minnepls = 1234 >>> print(f"minnepls Hex: {minnepls|0:x}") minnepls Hex: 4d2 >>> print(f"minnepls Octal: {minnepls|0:o}") minnepls Octal: 2322 >>> print(f"minnepls Decimal: {minnepls|0:}") minnepls Decimal: 1234 >>>

[pythonper]

Thank you for the quick reply, Larz.
The number conversion between int,hex etc seems ok. Int 3360 becomes hex 0xd20. How would you convert it to b'\x0d\x20' ? When running struct it just becomes b' \r'

1	#print(struct.pack("<H", 3360))

Output:
b' \r'

[Larz60+]

see: https://docs.python.org/3/library/functi...func-bytes