flyTo = input("Where would you like to fly? ")
if flyTo == flyTo.isdigit():
print("You accidentally added a number")
elif flyTo == flyTo.isalpha():
print("Okay, we are going to {} ".format(flyTo))
else:
print("??")k don't laugh
no matter what is entered,
it says: "??"
I want it to check if there are numbers.. and if so, to say "you accidentally added a number"
how would i proceed with allowing letters, not numbers?
thanks
Hi Sp00f,
What do you expect your line 2 to do exactly, step by step?
Same question for line 4.
You can test these things easily in python interactive console.
(Apr-05-2017, 07:20 PM)Kebap Wrote: [ -> ]Hi Sp00f,
What do you expect your line 2 to do exactly, step by step?
Same question for line 4.
You can test these things easily in python interactive console.
hello,
i want it to check the flyTo = input()
to see if there are numbers, what so ever.. and if so, to say:
print("there was a number in your flyTo = input()")
and then continue with what it is doing..
and as for line 4, I guess the exact opposite.. i want it to check and see if there are letters
>>> x='test'
>>> x==x.isdigit()
False
>>> x==x.isalpha()
False
>>> x.isalpha()
True
>>> y='123'
>>> y.isdigit()
True
you are comparing string (the user input) with boolean (the result of isdigit and isalpha).
That would always evaluates to False and your else is executed.
flyTo = input("Where would you like to fly? ")
if flyTo.isalpha():
print("Okay, we are going to {} ".format(flyTo))
elif any(c.isdigit() for c in flyTo):
print("You accidentally added a number")
else:
print("??")however I would skip the elif altogether
(Apr-05-2017, 08:03 PM)buran Wrote: [ -> ]you are comparing string (the user input) with boolean (the result of isdigit and isalpha).
That would always evaluates to False and your else is executed.
flyTo = input("Where would you like to fly? ")
if flyTo.isalpha():
print("Okay, we are going to {} ".format(flyTo))
elif any(c.isdigit() for c in flyTo):
print("You accidentally added a number")
else:
print("??")however I would skip the elif altogether
oh, i was comparing a string to a boolean?
can you elaborate on, "any(c.isdigit() for c in flyTo):"
thanks a lot
(Apr-05-2017, 08:17 PM)Sp00f Wrote: [ -> ]can you elaborate on, "any(c.isdigit() for c in flyTo):"
thanks a lot
In slo-mo:
for c in flyTo in an iterator... it iterates each element of flyTo. Since flyTo is a string the elements are characters
c.isdigit() is True if c is a digit
for c in flyTo builds a list of True or False, once for each character
any(some list) is True if there is at least one element that evaluates to True in the list
So
any(c.isdigit() for c in flyTo) evaluates to True is at least one character of
flyTo is a digit.
A different way of doing it:
len(flyTo)!=len(flyTo.translate(None,'0123456789'))
oh, i see..
why put c.digit()?
i tried x.digit(), and that worked as well.
can you explain what this is doing?
(Apr-05-2017, 10:56 PM)Sp00f Wrote: [ -> ]i tried x.digit(), and that worked as well.
The name is not important "rubberduck" is now temporarily assigning to each element in string flyTo.
>>> flyTo = 'yes9'
>>> any(rubberduck.isdigit() for rubberduck in flyTo)
True
When say "not important" so is
c much better than rubberduck when iterate over
characters.
To see each value can use list comprehension.
>>> flyTo = 'yes9'
>>> [rubberduck.isdigit() for rubberduck in flyTo]
[False, False, False, True]
Interactive shell can give info about a lot of stuff.
>>> help(any)
Help on built-in function any in module builtins:
any(...)
any(iterable) -> bool
Return True if bool(x) is True for any x in the iterable.
If the iterable is empty, return False.
>>> flyTo = 'yes9'
>>> help(flyTo.isdigit)
Help on built-in function isdigit:
isdigit(...) method of builtins.str instance
S.isdigit() -> bool
Return True if all characters in S are digits
and there is at least one character in S, False otherwise.