re

[menator01]

Trying to understand regexp a little.
Taking this string 01-09- Money Honey, I'm trying to get just the Money Honey part.
the closest I've gotten is this output

Output:
['', '', '-', '', '', '- Money Honey', '']

using

patt = '(\D*)'
print(re.findall(patt, display_label))

any help is much appreciated

[snippsat]

'm trying to get just the Money Honey part.

Something like this.

>>> import re 
>>> 
>>> s = '01-09- Money Honey'
>>> re.findall(r'\w+\s\w+', s)
['Money Honey']
>>> 
>>> r = re.search(r'(\w+\s\w+)', s)
>>> r.group(1)
'Money Honey'

[menator01]

'm trying to get just the Money Honey part.

Something like this.

>>> import re 
>>> 
>>> s = '01-09- Money Honey'
>>> re.findall(r'\w+\s\w+', s)
['Money Honey']
>>> 
>>> r = re.search(r'(\w+\s\w+)', s)
>>> r.group(1)
'Money Honey'

Many thanks, that has gave me something to play around with.