Regex - Pass Flags as a function argument?

[muzikman]

Greetings,

I am just playing around with possibly making some methods for my own class for regex. I have a slight problem. Take a look at the search function and tell me how I would add the flags as a parameter for that function.

flags = re.VERBOSE | re.IGNORECASE 

def search(pattern, string): # How can I pass the flags as a parameter to this function?
    
    result = re.search(pattern, string, flags = re.VERBOSE | re.IGNORECASE) # I want to pass these as an argument to the 'search' function.
    
    if result is None:
        return None
    else:
        return result

def regex(func, pattern, string):
    return func(pattern, string)


string = "This is a string with two phone numbers 555-555-5555 and 555-555-5555"
pattern = r"\d{3}-\d{3}-\d{4}"

result = regex(search, pattern, string)
print(result)

Thank you
Matt

[snippsat]

Like this,so if look regex source code they do same with flags=0.
This is kind of double up just use the search function

import re

def search(pattern, string, flags=0):
    result = re.search(pattern, string, flags) # I want to pass these as an argument to the 'search' function.
    if result is None:
        return None
    else:
        return result

if __name__ == '__main__':
    string = "This is a string with two phone numbers 555-555-5555 and 555-555-5555"
    pattern = r"\d{3}-\d{3}-\d{4}"
    flags = re.VERBOSE | re.IGNORECASE
    result = search(pattern, string, flags)
    print(result)

The argument given has to be same format then get parsing | for free.
Them do some magic to join | in parameter,just to take out 2 lines.

res = '|'.join(members)
globals().update(RegexFlag.__members__)

[muzikman]

You're correct. There is some redundancies here and that's the first indication that I should stay away for it. I was playing with passing functions as arguments and just wanted to see if it was possible.

Thanks for your help. I just realized. The numbers in the string area real. So, I need to get rid of them. Could you edit your post and remove them and I will do the same? Or as Admin, delete it; if you feel there is no value to the post.

Thank you

Like this,so if look regex source code they do same with flags=0.
This is kind of double up just use the search function

import re

def search(pattern, string, flags=0):
    result = re.search(pattern, string, flags) # I want to pass these as an argument to the 'search' function.
    if result is None:
        return None
    else:
        return result

if __name__ == '__main__':
    string = "This is a string with two phone numbers 555-555-5555 and 555-555-5555"
    pattern = r"\d{3}-\d{3}-\d{4}"
    flags = re.VERBOSE | re.IGNORECASE
    result = search(pattern, string, flags)
    print(result)

The argument given has to be same format then get parsing | for free.
Them do some magic to join | in parameter,just to take out 2 lines.

res = '|'.join(members)
globals().update(RegexFlag.__members__)

[muzikman]

Can you please remove the phone numbers from your post. They are real phone numbers. I forgot to remove them before posting.

Thanks.

Like this,so if look regex source code they do same with flags=0.
This is kind of double up just use the search function

import re

def search(pattern, string, flags=0):
    result = re.search(pattern, string, flags) # I want to pass these as an argument to the 'search' function.
    if result is None:
        return None
    else:
        return result

if __name__ == '__main__':
    string = "This is a string with two phone numbers "
    pattern = r"\d{3}-\d{3}-\d{4}"
    flags = re.VERBOSE | re.IGNORECASE
    result = search(pattern, string, flags)
    print(result)

The argument given has to be same format then get parsing | for free.
Them do some magic to join | in parameter,just to take out 2 lines.

res = '|'.join(members)
globals().update(RegexFlag.__members__)

[muzikman]

Please remove phone numbers.

Like this,so if look regex source code they do same with flags=0.
This is kind of double up just use the search function

import re

def search(pattern, string, flags=0):
    result = re.search(pattern, string, flags) # I want to pass these as an argument to the 'search' function.
    if result is None:
        return None
    else:
        return result

if __name__ == '__main__':
    string = "This is a string with two phone numbers "
    pattern = r"\d{3}-\d{3}-\d{4}"
    flags = re.VERBOSE | re.IGNORECASE
    result = search(pattern, string, flags)
    print(result)

The argument given has to be same format then get parsing | for free.
Them do some magic to join | in parameter,just to take out 2 lines.

res = '|'.join(members)
globals().update(RegexFlag.__members__)

[snippsat]

Please remove phone numbers.

Phone numbers is removed.

Or as Admin, delete it; if you feel there is no value to the post.

We do not delete post if not spam or other silliness,it can be value for someone we try not to interfere in that decision.

[muzikman]

Please remove phone numbers.

Phone numbers is removed.

Thank you.