Simple encoding code

[ebolisa]

Hi,

This simple encoding code converts text to ASCII and adds a one digit number to it. It seems to work ok, but while testing it, I noticed that if a 'v' is used, it's converted to ' ' when a 9 is added to it. (probably bc it's hitting ascii 127 - delete). Is there a way to fix it?

TIA

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encoded_txt = '' key = 0     def encode_text():     global encoded_txt, key     arry = []       txt = input("Enter an alphanumeric text: ")     while True:         try:             key = int(input('Enter a single digit number: '))             if key > 9:                 n = 1 / 0  # force to fail             break         except:             print("That's not a valid option!")       # fill array with entered text     for _ in range(len(txt)):         arry.append(txt[_])       # add pass to characters     for char in range(len(arry)):         x = ord(arry[char]) + key         # convert ascii to char         encoded_txt += chr(x)       print("Encoded text:", encoded_txt)     encode_text()

Output:
Enter an alphanumeric text: vince
Enter a single digit number: 9
New text: rwln
Decoded text: vince

[deanhystad]

Limit your alphabet to only visible characters. This example limits the alphabet to upper and lowercase letters,

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import string    letters = string.ascii_uppercase + string.ascii_lowercase   def encode_text(text, shift):     code = dict(zip(letters, letters[shift:] + letters[:shift]))     return "".join([code[letter] for letter in text])   encoded = encode_text("vince", 9) print(encoded, encode_text(encoded, -9))

[ebolisa]

Limit your alphabet to only visible characters. This example limits the alphabet to upper and lowercase letters,

Thank you. It works even with a little modification:

1	letters = string.ascii_letters + string.digits + string.punctuation

[deanhystad]

Maybe use ascii_printable. If you want punctuation you probably also want whitespace.