What does this mean?

[Giulio]

hello,
I am a beginner in python. I just started learning python in school 3 days ago.
I was wondering why this becomes true and false:

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0 == (1 == 2) true 0 == 1 == 2 false

what difference do the brackets make so it becomes true?

[wavic]

0 == ( 1 == 2 )
true
( 1 == 2 ) evaluates to False. 0 == False evaluates to True because 0, None and an empty value in Python are False.

0 == 1 == 2
False
0 == 1 evaluates to False. False == 2 evaluates to False because all numbers which are not 0 are evaluated to True. So False is not euqal to True

[Mekire]

0 == False evaluates to True because 0, None and an empty value in Python are False.

This isn't quite correct.  0 and False are the same value (not the same object).  False is technically a Boolean type but it is indistinguishable from 0 for all practical purposes.

None and empty sequences on the other hand are falsey values, but they are not equal to False (or 0).

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>>> 0 == False True >>> None == False False >>> () == False False >>>

[wavic]

This is what I mean:

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>>> bool(0) False >>> if 0: ...     print('True') ... >>> bool(None) False >>> if None: ...     print('True') ... >>> bool([]) False >>> if []: ...     print('True') ... >>>

[Mekire]

Quite aware of that, however the way you stated it (perhaps due to language) was not accurate.  His used neither bool nor a syntax which forced the expression to be evaluated in a boolean context.

Just as 2 == True is a false statement regardless of the fact that 2 would evaluate to True in a boolean context.

[wavic]

Yes, perhaps because my the English is not my native language. However, what I've said is that it evaluates to True or False. Not that is True or False.