Dynamic Formatting of String

[mikera1979]

I'm having some issues figuring out a way to transform a random number, that ranges from 2-5 characters in length. I'm trying to format the first 3 characters, regardless of spaces, to the following format.

Input = '12345'
Expected_Result = '1 2/3'

This is what I have so far, but it is not dynamic with spaces. Any help will be appreciated.

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bit_size= '618'   print('{} {}/{}'.format(*bit_size))

[Larz60+]

use double slash in print statement.
You need to escape the '/' which is itself an escape character

[mikera1979]

use double slash in print statement.
You need to escape the '/' which is itself an escape character

So I was able to get a little further after working on it for a few hours, but I'm still hitting a roadblock with allowing for a dynamic input. For example, the below output is constricted by the formatting code I've entered and is giving me a Tuple Index error. Any thoughts on how I can change that to allow for a return of values 1-4 numbers in length?

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size = '13 1/8' #grabs numeric values in string and concatenates def get_num(x):     return str(''.join(ele for ele in x if ele.isdigit()))   x = get_num(size) y = int(x)   #rules to remove leading 1s if int(str(y)[:1]) == 1:     if int(str(y)[1]) != 1:         print('{} {}/{}'.format(*x))     else:         print('{}{} {}/{}'.format(*x)) else:     print('{}{} {}/{}'.format(*x))