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+--- Thread: Need help with simple calculator. (/thread-12773.html)
Need help with simple calculator. - ghost0fkarma - Sep-11-2018
def main():
choice = input("Add or Sub? ")
if choice == "Add":
Add1()
else:
Sub1()
def Add1():
addchoice = str(input("Pick a number. "))
addchoice1 = str(input("Pick another number. "))
addconv = int(addchoice) + int(addchoice1)
addconv1 = str(addconv)
print("Your answer is:" + " " + addconv1)
exitcom()
def Sub1():
subchoice = str(input("Pick a number. "))
subchoice1 = str(input("Pick another number. "))
subconv = int(subchoice) - int(subchoice1)
subconv1 = str(subconv)
print("Your answer is:" + " " + subconv1)
main()
def exitcom():
exitcom1 = input("Would you like to make another calculation? (Y/N) --> ")
if exitcom1 == "Y" or "y":
main()
if exitcom1 == "n" or "N":
exit()
main()When running exitcom(), no matter if I type "y" or "n" I'm always returned back to main(). I want it to kill the program when n is type.
RE: Need help with simple calculator. - buran - Sep-11-2018
https://python-forum.io/Thread-Multiple-expressions-with-or-keyword
RE: Need help with simple calculator. - ghost0fkarma - Sep-11-2018
Thank you good sir :)
RE: Need help with simple calculator. - woooee - Sep-11-2018
Lay it out this way
def Add1():
addchoice = input("Pick a number. ")
print("addchoice is a", type(addchoice))
addchoice1 = input("Pick another number. ")
addconv = int(addchoice) + int(addchoice1)
## addconv1 = str(addconv)
print("Your answer is: ", addconv)
## exitcom()
def Sub1():
subchoice = input("Pick a number. ")
subchoice1 = input("Pick another number. ")
subconv = int(subchoice) - int(subchoice1)
## subconv1 = str(subconv)
print("Your answer is: ", subconv)
## main()
again="y"
while again.lower() == "y":
choice = input("Add or Sub? ")
if choice in ("Add", "Sub"):
if choice == "Add":
Add1()
else:
Sub1()
else:
print("Not a valid option")
again=input("Would you like to play again? (y or n) ")