Need help with simple calculator.

[ghost0fkarma]

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def main():     choice = input("Add or Sub? ")     if choice == "Add":         Add1()     else:         Sub1()   def Add1():     addchoice = str(input("Pick a number. "))     addchoice1 = str(input("Pick another number. "))     addconv = int(addchoice) + int(addchoice1)     addconv1 = str(addconv)     print("Your answer is:" + " " + addconv1)     exitcom()       def Sub1():     subchoice = str(input("Pick a number. "))     subchoice1 = str(input("Pick another number. "))     subconv = int(subchoice) - int(subchoice1)     subconv1 = str(subconv)     print("Your answer is:" + " " + subconv1)     main()       def exitcom():     exitcom1 = input("Would you like to make another calculation? (Y/N) --> ")     if exitcom1 == "Y" or "y":         main()     if exitcom1 == "n" or "N":         exit()           main()

When running exitcom(), no matter if I type "y" or "n" I'm always returned back to main(). I want it to kill the program when n is type.

[buran]

https://python-forum.io/Thread-Multiple-...or-keyword

[ghost0fkarma]

Thank you good sir :)

[woooee]

Lay it out this way

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def Add1():     addchoice = input("Pick a number. ")     print("addchoice is a", type(addchoice))     addchoice1 = input("Pick another number. ")     addconv = int(addchoice) + int(addchoice1) ##    addconv1 = str(addconv)     print("Your answer is: ", addconv) ##    exitcom()   def Sub1():     subchoice = input("Pick a number. ")     subchoice1 = input("Pick another number. ")     subconv = int(subchoice) - int(subchoice1) ##    subconv1 = str(subconv)     print("Your answer is: ", subconv) ##    main()   again="y" while again.lower() == "y":     choice = input("Add or Sub? ")     if choice in ("Add", "Sub"):         if choice == "Add":             Add1()         else:             Sub1()     else:         print("Not a valid option")     again=input("Would you like to play again? (y or n) ")