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+--- Thread: Most efficient way of reshaping a list-array structure (/thread-21332.html)
Most efficient way of reshaping a list-array structure - midarq - Sep-25-2019
Hi!
I'm dealing with huge data and I'm looking for an efficient way to reshape my list of arrays. Here is my solution which I find to be slow
#x is an input of shape [file,measurement, array(n,r)], i.e. #len(x) returns file #len(x[0]) returns measurement #x[0][0].shape returns (n,r)the output I require:
#new_x is a list of arrays, its shape is [file*measurement*n, array(r)]I'm using the following code:
new_x=[]
for ii in range(len(x)):
for jj in range(len(x[0])):
for kk in range(len(x[0][0])):
new_x.append(x[ii][jj][kk])Is there a more efficient way?Thank you for your help.
RE: Most efficient way of reshaping a list-array structure - Gribouillis - Sep-25-2019
What about
for xi in x:
for xij in xi:
new_x.extend(xij)
RE: Most efficient way of reshaping a list-array structure - midarq - Sep-25-2019
Much faster, thank you!