Check matrix... - Printable Version

Check matrix... - Printable Version

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Check matrix... - jkk30 - Apr-12-2017

Hi
I need a little help.
How to check whether a matrix corresponding to the rules?

Matrix =  [[1, 30, 34, 55, 75], 
             [10, 16, 40, 50, 67], 
             [5, 20, 38, 48, 61], 
             [4, 26, 43, 49, 70], 
             [15, 17, 33, 51, 66]]

rules :The first column 1- 15 , second column 16-30,third column 31-45,fourth column 46-60,fifth column 61-75.... (like bingo ticket)

RE: Check matrix... - micseydel - Apr-12-2017

What have you tried?

RE: Check matrix... - jkk30 - Apr-12-2017

I find the columns, but I do not know how to control them,....

I find the columns like this:

tabel = [[1, 30, 34, 55, 75], 
             [10, 16, 40, 50, 67], 
            [5, 20, 38, 48, 61], 
            [4, 26, 43, 49, 70], 
            [15, 17, 33, 51, 66]]


for veerg in range(len(tabel[0])):
   for rida in range(len(tabel)):
       print(tabel[rida][veerg]) 
   print()

RE: Check matrix... - Ofnuts - Apr-12-2017

Put the ranges in a list:

ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]

Then when you scan a line, you use the index of the item to retrieve the corresponding element in ranges and compare its value with the two limits.

An even more pythonic way is to:

 iterate lines
    zip(line,ranges)
    iterate result which are (line_item, (min,max)) and compare

RE: Check matrix... - jkk30 - Apr-13-2017

I stack in if . What do I need to write there to control columns

def on_bingo_tabel(bingo):
    for i in range(len(bingo)):
        for j in range(len(bingo[i])):
            if ????????: 
                return False
            
    return True        
  
    
    
bingo = [[1, 30, 34, 55, 75], 
        [10, 16, 40, 50, 67], 
        [5, 20, 38, 48, 61], 
        [4, 26, 43, 49, 70], 
        [15, 17, 33, 51, 66]]  


ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]


print(on_bingo_tabel(bingo))

RE: Check matrix... - Ofnuts - Apr-13-2017

(Apr-13-2017, 07:59 AM)jkk30 Wrote: I stack in if . What do I need to write there to control columns

def on_bingo_tabel(bingo):
    for i in range(len(bingo)):
        for j in range(len(bingo[i])):
            if ????????: 
                return False
            
    return True        
  
    
    
bingo = [[1, 30, 34, 55, 75], 
        [10, 16, 40, 50, 67], 
        [5, 20, 38, 48, 61], 
        [4, 26, 43, 49, 70], 
        [15, 17, 33, 51, 66]]  


ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]


print(on_bingo_tabel(bingo))

i-th element of line compared to the bounds from i-th element of ranges

The one-liner (don't put in your holework unless you really understand how it works):

def check(bingo):
    return any(any(not  minvalue <= actual <= maxvalue for actual,(minvalue,maxvalue) in zip(line,ranges)) for line in bingo)

RE: Check matrix... - jkk30 - Apr-14-2017

I found a solution :D

 def on_bingo_tabel(tabel):
    for i in range(len(tabel)):
        for j in range(len(tabel[i])):
            if tabel[i][j] < j*15+1 or tabel[i][j] > j*15+15 :
                return False
    return True

Thanks to all who contribute to thinking :D