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Apr-12-2017, 04:45 AM
(This post was last modified: Apr-12-2017, 08:32 AM by Kebap.)
Hi
I need a little help.
How to check whether a matrix corresponding to the rules?
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Matrix = [[1, 30, 34, 55, 75],
[10, 16, 40, 50, 67],
[5, 20, 38, 48, 61],
[4, 26, 43, 49, 70],
[15, 17, 33, 51, 66]]
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rules :The first column 1- 15 , second column 16-30,third column 31-45,fourth column 46-60,fifth column 61-75.... (like bingo ticket)
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Apr-12-2017, 05:35 AM
(This post was last modified: Apr-12-2017, 08:33 AM by Kebap.)
I find the columns, but I do not know how to control them,....
I find the columns like this:
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tabel = [[1, 30, 34, 55, 75],
[10, 16, 40, 50, 67],
[5, 20, 38, 48, 61],
[4, 26, 43, 49, 70],
[15, 17, 33, 51, 66]]
for veerg in range(len(tabel[0])):
for rida in range(len(tabel)):
print(tabel[rida][veerg])
print()
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Posts: 687
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Joined: Sep 2016
Apr-12-2017, 08:02 AM
(This post was last modified: Apr-12-2017, 08:33 AM by Kebap.)
Put the ranges in a list:
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ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]
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Then when you scan a line, you use the index of the item to retrieve the corresponding element in ranges and compare its value with the two limits.
An even more pythonic way is to:
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iterate lines
zip(line,ranges)
iterate result which are (line_item, (min,max)) and compare
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Unless noted otherwise, code in my posts should be understood as "coding suggestions", and its use may require more neurones than the two necessary for Ctrl-C/Ctrl-V.
Your one-stop place for all your GIMP needs: gimp-forum.net
Posts: 4
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I stack in if . What do I need to write there to control columns
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def on_bingo_tabel(bingo):
for i in range(len(bingo)):
for j in range(len(bingo[i])):
if ????????:
return False
return True
bingo = [[1, 30, 34, 55, 75],
[10, 16, 40, 50, 67],
[5, 20, 38, 48, 61],
[4, 26, 43, 49, 70],
[15, 17, 33, 51, 66]]
ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]
print(on_bingo_tabel(bingo))
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Apr-13-2017, 09:40 PM
(This post was last modified: Apr-13-2017, 09:40 PM by Ofnuts.)
(Apr-13-2017, 07:59 AM)jkk30 Wrote: I stack in if . What do I need to write there to control columns
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def on_bingo_tabel(bingo):
for i in range(len(bingo)):
for j in range(len(bingo[i])):
if ????????:
return False
return True
bingo = [[1, 30, 34, 55, 75],
[10, 16, 40, 50, 67],
[5, 20, 38, 48, 61],
[4, 26, 43, 49, 70],
[15, 17, 33, 51, 66]]
ranges=[(1,15) ,(16,30),(31,45),(46,60),(61,75)]
print(on_bingo_tabel(bingo))
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i-th element of line compared to the bounds from i-th element of ranges
The one-liner (don't put in your holework unless you really understand how it works):
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def check(bingo):
return any(any(not minvalue <= actual <= maxvalue for actual,(minvalue,maxvalue) in zip(line,ranges)) for line in bingo)
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Unless noted otherwise, code in my posts should be understood as "coding suggestions", and its use may require more neurones than the two necessary for Ctrl-C/Ctrl-V.
Your one-stop place for all your GIMP needs: gimp-forum.net
Posts: 4
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Joined: Apr 2017
I found a solution :D
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def on_bingo_tabel(tabel):
for i in range(len(tabel)):
for j in range(len(tabel[i])):
if tabel[i][j] < j*15+1 or tabel[i][j] > j*15+15 :
return False
return True
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Thanks to all who contribute to thinking :D
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