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+--- Thread: How to discard list repeat values (/thread-31685.html)
How to discard list repeat values - akanowhere - Dec-27-2020
Dears;
In the bellow list there repeats values in the last indice:
I need discard the the key and the value (all) if the value is repeated:
Exemple: list[0][2] is 3585 and list[4][2] are the same!!!
list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]
RE: How to discard list repeat values - buran - Dec-27-2020
Let's make the terminology right.
There are no repeating elements in this list. It's a list of lists. There are repeating elements in the list elements (i.e. in the sublists). Then this is not a mapping like dict. There are no key value pairs.
Finally - show what expected output is and what have you tried so far.
RE: How to discard list repeat values - akanowhere - Dec-27-2020
(Dec-27-2020, 08:17 PM)buran Wrote: Let's make the terminology right.
There are no repeating elements in this list. It's a list of lists. There are repeating elements in the list elements (i.e. in the sublists). Then this is not a mapping like dict. There are no key value pairs.
Finally - show what expected output is and what have you tried so far.
Discar the repeated element in sub list[4]
1
list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]1
Output:list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913]]RE: How to discard list repeat values - buran - Dec-27-2020
it's still unclear
why do you remove the last element (presumably from your first post - because of repeating 3585) and yet preserve repeating 3847
RE: How to discard list repeat values - akanowhere - Dec-27-2020
(Dec-27-2020, 08:27 PM)buran Wrote: it's still unclear
why do you remove the last element (presumably from your first post - because of repeating 3585) and yet preserve repeating 3847
sorry..... it´s will be removed too..but lets keep one repeat.....
list = [['seg', 'João', 3585], ['qui', 'João', 3850], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]
Output:list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913]]RE: How to discard list repeat values - perfringo - Dec-28-2020
Don't use list as name.
>>> list('abc')
['a', 'b', 'c']
>>> list = ['a', 'b', 'c']
>>> list('abc')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
>>> list
['a', 'b', 'c']
RE: How to discard list repeat values - Pedroski55 - Dec-28-2020
# use set to get rid of duplicates like this
numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers = set(numbers)
# this works great: splat it!
numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers2 = {*numbers}
# you can't do this, because a list can't be a member of a set
numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers = {numbers}
# to your problem
mylist = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]
# an empty set
no_repeats = set()
# add the contents of the sub-lists to no_repeats
for item in mylist:
aset = set(item)
no_repeats.update(aset)
# this returns: {3585, 3847, 3913, 'seg', 'qui', 'João', 'qua'}
# if you need a list: result = list(no_repeats)
# if you need a dictionary from this list, check out your last post
RE: How to discard list repeat values - akanowhere - Dec-28-2020
(Dec-28-2020, 04:56 AM)perfringo Wrote: Don't use list as name.
>>> list('abc') ['a', 'b', 'c'] >>> list = ['a', 'b', 'c'] >>> list('abc') Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: 'list' object is not callable >>> list ['a', 'b', 'c']
Tks a lot i was wrote lista...it was on portugues,,,when I tranlate I forgot that list is a reserved word....