How to discard list repeat values

[akanowhere]

Dears;

In the bellow list there repeats values in the last indice:

I need discard the the key and the value (all) if the value is repeated:
Exemple: list[0][2] is 3585 and list[4][2] are the same!!!

 list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]

[buran]

Let's make the terminology right.
There are no repeating elements in this list. It's a list of lists. There are repeating elements in the list elements (i.e. in the sublists). Then this is not a mapping like dict. There are no key value pairs.
Finally - show what expected output is and what have you tried so far.

[akanowhere]

Let's make the terminology right.
There are no repeating elements in this list. It's a list of lists. There are repeating elements in the list elements (i.e. in the sublists). Then this is not a mapping like dict. There are no key value pairs.
Finally - show what expected output is and what have you tried so far.

Discar the repeated element in sub list[4]

1

list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]

1

Output:
list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913]]

[buran]

it's still unclear
why do you remove the last element (presumably from your first post - because of repeating 3585) and yet preserve repeating 3847

[akanowhere]

it's still unclear
why do you remove the last element (presumably from your first post - because of repeating 3585) and yet preserve repeating 3847

sorry..... it´s will be removed too..but lets keep one repeat.....

list = [['seg', 'João', 3585], ['qui', 'João', 3850], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]

Output:
list = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913]]

[perfringo]

Don't use list as name.

>>> list('abc')
['a', 'b', 'c']
>>> list = ['a', 'b', 'c']
>>> list('abc')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
>>> list
['a', 'b', 'c']

[Pedroski55]

# use set to get rid of duplicates like this

numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers = set(numbers)

# this works great: splat it!

numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers2 = {*numbers}

# you can't do this, because a list can't be a member of a set

numbers = [1, 2, 3, 1, 2, 3, 4, 1]
unique_numbers = {numbers}

# to your problem

mylist = [['seg', 'João', 3585], ['qui', 'João', 3847], ['seg', 'João', 3847], ['qua', 'João', 3913], ['qua', 'João', 3585]]

# an empty set

no_repeats = set()

# add the contents of the sub-lists to no_repeats

for item in mylist:
    aset = set(item)
    no_repeats.update(aset)

# this returns: {3585, 3847, 3913, 'seg', 'qui', 'João', 'qua'}
# if you need a list: result = list(no_repeats)
# if you need a dictionary from this list, check out your last post

[akanowhere]

Don't use list as name.

>>> list('abc')
['a', 'b', 'c']
>>> list = ['a', 'b', 'c']
>>> list('abc')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
>>> list
['a', 'b', 'c']

Tks a lot i was wrote lista...it was on portugues,,,when I tranlate I forgot that list is a reserved word....