Fixing "PermissionError: [Errno 13] Permission denied"

[DeaD_EyE]

Here a more simple version, not tested much:

from pathlib import Path
from typing import Generator


FileList = Generator[Path, None, None]


def get_list_of_files(base_folder: Path) -> FileList:
    for entry in base_folder.rglob('*'):
        # Skip all hidden files and folders
        if entry.name.startswith('.'):
            continue
            
        if entry.is_file():
            yield entry


base_folder = Path.home() / 'Development'
files = list(get_list_of_files(base_folder))

for file in files:
    print(file)

Btw. the typehint stuff is not needed, but they could help an IDE to check for errors.
I changed the FileList, because it's now a generator, which yields Path objects.
You can make the homepath with Path.home() and join paths with /.
Makes it more readable. Also the recursion is not needed and can fail, if your directory tree is deeper than 1000.
The method rglob('*') does the job and find all files and directories recursive.

Now to you other problem. You can extend the function, to take a argument for extensions you want to process.

from pathlib import Path

my_extensions = ['.txt', '.odt', '.csv']
my_path = Path('/A/directory/somewhere/that/does/not.exist/file.txt')
print('The suffix is:', my_path.suffix)

if my_path.suffix not in my_extensions:
    print(my_path, 'has not the allowed file extension')

Instead of print something, you continue in the for-loop, to skip this element.

---

By the way, you could iterate over the generator. Before you provided a list as argument, which was modified inside the function. Now the function is turned into a generator (the yield keyword is inside). For each iteration the generator returns a path.

If the file-list is not needed, you could remove files = []

 
for file in get_list_of_files(base_folder):
    print(file)
    my_zipfile = zipfile.ZipFile(file)
    my_zipfile.extractall(r'C:\Users\username\My_Dataset\new')

Maybe the zipfile Module doesn't understand the Path object (haven't tested yet), but a path could converted into a string with str(file).