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[jmabrito]

You've got a for loop that only ever runs one time: for _ in range(1): on line 9. You can just get rid of that (since it only ever runs once, the same thing will happen whether it's there or not). Then, once there's only a single loop, you can use continue to skip the rest of the loop body. And I *think* that's what you're trying to accomplish.

Try this out, please:

import random
import pyttsx3
for r in range(15):
    fname = "bjjj.txt"
    with open(fname) as f:
        numbers = f.readline().strip().split()

    # print the numbers in the file:
    print(numbers)

    k = str(random.randint(1, 16))
    if k not in numbers:
        print(f'{k} não EXISTE')
        numbers.append(k)
    else:
        print(f'{k} EXISTE')
        # skip the rest of the for loop
        continue

    with open(fname, 'w') as f:  # open file in write mode
        f.write(f'{" ".join(numbers)}\n')

        # vai ler o ficheiro txt de nome ler
        # Instrucoes em https://youtu.be/BtwHAvsNaA8
        # import pyttsx3 #pip instal pyttsx3
        # le o texto que esta guardado em um arquivo .txt

    with open('C:/Users/José Brito/AppData/Local/Programs/Python/Python39/WORK/ler.txt', 'r', encoding="utf8") as f:
        texto = f.read()
        texto = 'Saiu o número  ',  k  # não lê o ficheiro
        speaker = pyttsx3.init()  # inicia serviço biblioteca
        voices = speaker.getProperty('voices')  # metodo de voz
        # ver as vozes instaladas na maquina
        for voice in voices:
            # traz os idiomas de voz instalados em sua maquina
            print(voice, voice.id)

        # define a voz padrao, no meu caso o portugues era o[2] (iniciando do zero)
        speaker.setProperty('voice', voices[1].id)
        rate = speaker.getProperty('rate')  # nao exiuste a voz portuguesa
        # muda velocidade da leitura, quando menor mais lento
        speaker.setProperty('rate', rate-(200))
        print(texto)  # escreve o texto na tela
        speaker.say(texto)  # define o texto que será lido
        speaker.runAndWait()  # le o texto

[quote]
Worked perfectly. I introduced these changes
print ®
a = input ("Enter the number:")
if a == '999':
sys.exit ()
else:
print ('ok')

and the numbers are no longer announced.
what he intended was that when the number already existed he would go to the instruction
k = str (........
already tried as with While, to no avail
Thanhs
[\quote]

Larz60+ write Feb-11-2021, 11:01 PM:
Please use proper bbcode see: https://python-forum.io/misc.php?action=help&hid=25

python tags for code
quote for quotes only