Removing nan values from a dict

[menator01]

nan = 0
mylist = [438.4, 439.18, 439.9, 440.21999999999997, 440.38, 441.08000000000004, nan, nan, nan, nan]

for i in range(len(mylist)):
    if i >= 6:
        mylist.pop()

print(mylist)

Output:
[438.4, 439.18, 439.9, 440.21999999999997, 440.38, 441.08000000000004]

Thank you so much sir, but the len of the list is not fixed it will be determine by the bars the traded cryptocurrency

This will not matter the list length. You should use one of the more experienced programmers suggestions though.

#! /usr/bin/env python3

nan = 0
mylist = [438.4, 439.18, 439.9, 440.21999999999997, 440.38, 441.08000000000004, nan, nan, nan, nan]

for i in range(len(mylist)):
    if 0 in mylist:
        mylist.pop()

print(mylist)