Find numbers using Regex

[giddyhead]

Hi.

Does this do what you want?

import re

string = '1the 5one 5529care 30over'

for i in range(len(string)):
    digit = re.search('[0-9]', string[i])
    if digit:
        print(f'Found digit {string[i]} at position {i}')

Output:
Found digit 1 at position 0
Found digit 5 at position 5
Found digit 5 at position 10
Found digit 5 at position 11
Found digit 2 at position 12
Found digit 9 at position 13
Found digit 3 at position 19
Found digit 0 at position 20

{edit to remove my debug line of code}

Hi,

Thanks for the reply with information and help. Unfortunately it finds all the numbers within. The numbers in bold below is what I am looking to get rid of. The following is a sample but contains the format of the text in one of the lists which contain numbers throughout:
Hope it clarifies. Thanks in advance.

25 - not this number

the cow just over the moon and the sun is in 1the sky

26 - not this number

5one day is soon and soon is near take 5529care, 30over and out

59 - not this number

The covers at near the back of the 59closet, and when found have them place on the each of the beds. However you see the pillow cases use the ones on the 9second shelve.

---

Maybe like this?

import re
mylist = ['1the', '5one', '5529care', '30over', '55more66']
# re.findall returns a list
for s in mylist:
    result = re.findall('[0-9]+', s)
    print(s)
    print(result)

Hey,
Thanks for the help. Unfortunately due to numbers spread throughout each list it finds all the numbers. Looking to only find the numbers attached to words in bold. I have included a sample list for reference.
Thanks

25 - not this number

the cow just over the moon and the sun is in 1the sky

26 - not this number

5one day is soon and soon is near take 5529care, 30over and out

59 - not this number

The covers at near the back of the 59closet, and when found have them place on the each of the beds. However you see the pillow cases use the ones on the 9second shelve.